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3 years ago

What color is mercury

2 answers:

7 0

Hello!
If you are referring to the mercury substance, mercury is a bright red color, usually used in early thermometers and is deadly if humans have a lot of constant with this substance

Alisiya [41]3 years ago

6 0

Mercury as in the element, or the planet?
Well, i'll tell you both, just in case.
The planet is a dark grey,
and the element is kind-of a silvery-white color.
Hope this helps!
Stay smart,
~{Dunsforhands}

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What is the moment of inertia of a disc of mass 5kg and radius 10cm?

vodka [1.7K]

Answer:

500

Explanation:

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3 years ago

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Thickening agents are flavorless starches or proteins commonly used in cooking; such as thickening gravy for Thanksgiving dinner

Bingel [31]

Starches are more than chains of sugar granules strung together. In the case of corn starch, it is actually millions of these molecules packed into very discrete granules, which cannot be seen by the naked eye. Putting corn starch into cold water, nothing happens because cold water does not dissolve these granules. Putting it into hot water (like cooking gravy) however, these granules dissolve and create bonds between the water and the starch.

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3 years ago

Explain how sound travels from your vocal cords to your friend’s ear when you talk

AysviL [449]

Answer:

Your vocal cords vibrate and then travel through the air to your friends ear. ... loudness is a humans perception of sound intensity, as intensity of a sound wave increases the loudness of a sound wave increases.

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Sound waves enter the outer ear and travel through a narrow passageway called the ear canal, which leads to the eardrum. The eardrum vibrates from the incoming sound waves and sends these vibrations to three tiny bones in the middle ear.

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3 years ago

A particle moves with acceleration function a(t) = 5 + 4t - 2t^2. Its initial velocity v(0) = 3 m/s and its initial displacement

eimsori [14]

Answer:

Its position after 4 seconds is 62 meters.

Explanation:

It is given that,

The acceleration of the particle is given by equation :

$a(t)=5+4t-2t^2$

Also, $a=\dfrac{dv}{dt}$

$v=\int\limits {a.dt}$

$v=\int\limits {(5+4t-2t^2).dt}$

$v=5t+2t^2-\dfrac{2}{3}t^3+c$

At t = 0, $v(0)=3\ m/s$ . So, c = 3

$v=5t+2t^2-\dfrac{2}{3}t^3+3$

Also, $v=\dfrac{ds}{dt}$ , s is the position

$s=\int\limits {v.dt}$

$s=\int\limits {(5t+2t^2-\dfrac{2}{3}t^3+3).dt}$

$s=\dfrac{5}{2}t^2+\dfrac{2}{3}t^3-\dfrac{t^4}{6}+3t+c'$

At t = 0, $s(0)=10\ m$ . So, c' = 10

$s=\dfrac{5}{2}t^2+\dfrac{2}{3}t^3-\dfrac{t^4}{6}+3t+10$

At t = 4 s

$s=\dfrac{5}{2}(4)^2+\dfrac{2}{3}(4)^3-\dfrac{(4)^4}{6}+3(4)+10$

s = 62 m

So, at t = 4 seconds the position of the particle is 62 meters. Hence, this is the required solution.

5 0

3 years ago

The Event Horizon Telescope needs a 22 micro-arcsecond resolution to view the event horizon regions around black holes. If the a

likoan [24]

Answer:

14869817.395 m

Explanation:

$\theta$ =22 microarcsecond

λ = Wavelength = 1.3 mm

Converting to radians we get

$22\times 10^{-6}\frac{\pi}{180\times 3600}\ radians$

From Rayleigh Criterion

$\theta=1.22\frac{\lambda}{D}\\\Rightarrow D=1.22\frac{\lambda}{\theta}\\\Rightarrow D=1.22\frac{1.3\times 10^{-3}}{22\times 10^{-6}\frac{\pi}{180\times 3600}}\\\Rightarrow D=14869817.395\ m$

Diameter of the effective primary objective is 14869817.395 m

It is not possible to build one telescope with a diameter of 14869817.395 m. But, we need this type of telescope. So, astronomers use an array of radio telescopes to achieve a virtual diameter in order to observe objects that are the size of supermassive black hole's event horizon.

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3 years ago