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meriva
3 years ago
6

Help? Will give thanks if right (thank you)

Physics
1 answer:
qwelly [4]3 years ago
8 0

Hello there.

1.986*10^6

10^6=1,000,000

1.986*1,000,000

<u><em>Answer=1,986,000</em></u>

Explanation: First you had to ten to the six power of the ten with six times. It gave us 1000000 should be have six zeros at any time. Then you can multiply by 1.986*1000000=1,986,000 is the right answer. Hope this helps! Thank you for posting your question at here on Brainly. -Charlie

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A test rocket is launched vertically from ground level (y=0), at time t=0.0s. The rocket engine provides constant upward acceler
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From the definition of average velocity,

\bar v=\dfrac{\Delta y}{\Delta t}=\dfrac{49\,\mathrm m}t,

and the fact that constant acceleration means

\bar v=\dfrac{v_f+v_0}2=\dfrac{30\,\frac{\mathrm m}{\mathrm s}}2=15\,\dfrac{\mathrm m}{\mathrm s}

we can solve for the time t:

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3 years ago
If a skydiver jumps out of a plane horizontally (in other words with no initial vertical velocity), then what will her vertical
erastovalidia [21]

The final vertical velocity of the skydiver at 50.8 m of fall is 31.56 m/s.

<h3>Time of motion of the girl</h3>

The time of motion of the girl is calculated as follows;

h = vt + ¹/₂gt²

where;

  • v is initial vertical velocity = 0
  • t is time of motion
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Substitute the given parameters and solve for time of motion;

50.8 = 0 + ¹/₂(9.8)t²

2(50.8) = 9.8t²

101.6 = 9.8t²

t² = 101.6/9.8

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t = √10.367

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vf = vi + gt

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vf = 0 + 9.8(3.22)

vf = 31.56 m/s

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Learn more about vertical velocity here: brainly.com/question/24949996

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4 0
2 years ago
A uniform rod of length 50cm and mass 0.2kg is placed on a fulcrum at a distance of 40cm from the left end of the rod. At what d
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Answer:

x = 45 cm

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Given that,

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The centre of mass of the rod is at 25 cm.

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15\times 0.2=x\times 0.6\\\\x=\drac{3}{0.6}\\\\x=5\ cm

The distance from the left end is 40+5 = 45 cm.

Hence, at a distance of 45 cm from the left end it will balance the rod.

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How does emission spectra occur?
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