hola ya sabes la respuesta si si ,me la dices porfa
Answer:
Mass of the steel cube = 7800 kg
Volume of the steel = 1.025 cubic centimetre
Explanation:
Given:
The density of the steel = 7.8
Side of the cube = 12 cm
<u>(1)The mass of steel cube :</u>
We know that,

We are given with density and sides of the cube
then volume of the cube
=
= 
= 1000 cubic centimetre
Now


mass = 7800 kg
<u>(2)volume of steel:</u>
Given the mass = 8 kg

Substituting the values


volume = 1.025 cubic centimetre
Answer:
f this bs
Explanation:
no i will not answer this
Explanation:
1. Force applied on an object is given by :
F = W = mg
(a) A 160 lb human being, F = 160 lb
g = acceleration due to gravity, g = 32 ft/s²


m = 5 kg
(b) A 1.9 lb cockatoo, F = 1.9 lb


m = 0.059 kg
2. (a) A 2300 kg rhinoceros, m = 2300 kg

(b) A 22 g song sparrow, m = 22 g = 0.022 kg

Hence, this is the required solution.
Btu/(lb-°F) J/(g-°C i mean this is the correct answer