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vodka [1.7K]
4 years ago
8

Assuming motion is on a straight path what would result in two positive components of a vector

Physics
1 answer:
polet [3.4K]4 years ago
5 0
If the object being represented is going both up and to the right.
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A ball is launched with initial speed v from the ground level up a frictionless hill. The hill becomes steeper as the ball slide
Triss [41]

Answer:

H(max) = (v²/2g)

Explanation:

The maximum height the ball will climb will be when there is no friction at all on the surface of the hill.

Normally, the conservation of kinetic energy (specifically, the work-energy theorem) states that, the change in kinetic energy of a body between two points is equal to the work done in moving the body between the two points.

With no frictional force to do work, all of the initial kinetic emergy is used to climb to the maximum height.

ΔK.E = W

ΔK.E = (final kinetic energy) - (initial kinetic energy)

Final kinetic energy = 0 J, (since the body comes to rest at the height reached)

Initial kinetic energy = (1/2)(m)(v²)

Workdone in moving the body up to the height is done by gravity

W = - mgH

ΔK.E = W

0 - (1/2)(m)(v²) = - mgH

mgH = mv²/2

gH = v²/2

H = v²/2g.

7 0
3 years ago
Determine the minimum applied force p required to move wedge a to the right. the spring is compressed a distance of 185 mm. negl
Pie

By equation of equilibrium and friction:

Fb = Kx = 15(0.175) = 2.625 kN.

The wedge is on the verge of moving right then slipping will have to occur at both contact surfaces.

Fa = usNa = 0.35Na

Fb = 0.35Nb

Nb = 2.625 = 0; Nb = 2.625 kN

Nacos10 – 0.35Na sin 10 = 2.625 = 0

Na = 2.841 kN

P – (0.35 * 2.625) – 0.35 (2.841) cos 10 – 2.841 sin 10 = 0

P = 2.39 kN

7 0
4 years ago
The specific heat of copper is 0.093 cal/gC°, and the specific heat of aluminum is 0.22 cal/gC°. The same amount of energy appli
Aleks04 [339]

Answer:

higher temperature of copper.

Explanation:

less specific heat capacity.

8 0
3 years ago
A block of metal of density 3000 kg/m3 is 2m high and stands on a square base of side 0.5 m. Calculate:
labwork [276]

Answer:

1)  A = 0.25 m², 2) V = 0.5 m³, 3)   m = 1500 kg, 4) W = 14700 N,

5)  P = 58800 Pa

Explanation:

1) The area of ​​the base is square

          A = L²

         A = 0.5²

         A = 0.25 m²

2) The block is a parallelepiped

         V = A h

         V = 0.25 2

          V = 0.5 m³

3) Density is defined

           rho = m / V

           m = rho V

           m = 3000 0.5

           m = 1500 kg

4) The weight of a body is

           W = mg

            W = 1500 9.8

            W = 14700 N

5) The pressure is

             P = F / A

in this case the force is equal to the weight of the body

              P = 14700 / 0.25

              P = 58800 Pa

8 0
3 years ago
What are some of the causes that disrupt the natural balance of the ecosystem?
dangina [55]
Overpopulation of predators
5 0
3 years ago
Read 2 more answers
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