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Marat540 [252]
3 years ago
9

From the graph of Density vs. Concentration, created in Graph 1, what was the relationship between the concentration of the suga

r solution and the density of the sugar solution?

Chemistry
1 answer:
USPshnik [31]3 years ago
8 0

The graph is not given in the question, so, the required graph is attached below:

Answer:

According to the graph, the relationship between the density of the sugar solution and the concentration of the sugar solution is directly proportional to each other as they both are increasing exponentially.

The graph shows that, the density of sugar solution will increase with the increase in concentration of sugar in the solution.

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If a ball is running down a ramp, why is it that when you change the height of the ramp, the ... of the ramp, then you will increase the acceleration of a ball which rolls down the ramp.
8 0
4 years ago
Using the appropriate Ksp values, find the concentration of K+ ions in the solution at equilibrium after 600 mL of 0.45 M aqueou
Alekssandra [29.7K]

Answer:

[K⁺] = 0.107 M

[OH⁻] = 1.13 ×  10⁻⁹ M

Explanation:

600 mL of 0.45 M Cu(NO3)2 gives equal mole of Cu²⁺ and (NO₃)²⁻

⇒ 0.45 × 600 × 10⁻³

= 0.27 moles of Cu²⁺ and (NO₃)²⁻

450 mL of 0.25 M KOH gives equal moles of K⁺ and OH⁻

⇒ 0.25 × 450 × 10⁻³

= 0.1125 moles of K⁺ and OH⁻

Now after mixing 0.1125 moles of OH⁻ precipitates 0.05625 moles of Cu²⁺  (because 1 Cu²⁺  needs 2 OH⁻)

Therefore , moles of remaining Cu²⁺  = 0.27 - 0.05625

=0.21375 moles which is equal to :

⇒ 0.21375/(( 600+450))× 10⁻³

= 0.21375/1050 × 10⁻³

= 0.20357 M

Given that :

(Ksp for Cu(OH)2 is 2.6 ×  10⁻¹⁹)

We know that , Ksp = [Cu²⁺][OH⁻]²

2.6 ×  10⁻¹⁹ = 0.20357 × [OH⁻]²

[OH⁻]² = 2.6 ×  10⁻¹⁹/0.20357

[OH⁻] = 1.13 ×  10⁻⁹ M

[K⁺] = moles of K⁺ /total volume

[K⁺] = 0.1125 / 1050 × 10⁻³

[K⁺] = 0.107 M

6 0
3 years ago
A balloon filled with air has a volume of 4.24 liters at 23.00°C. If the balloon is cooled at constant pressure to 5.00°C, what
hammer [34]

Answer:

The new volume if the balloon is cooled at constant pressure is 3.98 L

Explanation:

The new volume is calculated using the Charles law formula

that is V1/ T1 = V2/T2 where,

V1 = 4.24 l

T1= 23c into kelvin = 23 +273 =296 K

T2 = 5.00 c into kelvin = 5.00 + 273 = 278 K

V2 = ?

by making V2 subject the subject of the formula by multiplying both side by T2

V2 = V1 xT2/ T1

V2 = (4.24 L x 278 K) / 296 k = 3.98 L

4 0
2 years ago
What material often called a shooting stars as it enters the Earth’s atmosphere
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What would be a comet

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A scoop of baking soda is added to a beaker containing vinegar. The baking soda disappears and bubbles are observed. This is an
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