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Hunter-Best [27]
3 years ago
15

What is the frequency of a transverse wave ?​

Physics
1 answer:
yuradex [85]3 years ago
7 0

Answer:

The number of complete vibration or wave made in

one second is called frequency.

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I'm not really sure how to go about creating the equation, can anyone help me?
AlexFokin [52]
The displacement vector (SI units) is
\vec{r} =At\hat{i}+A[t^{3}-6t^{2}]\hat{j}

The speed is a scalar quantity. Its magnitude is
v= \sqrt{A^{2}t^{2}+A^{2}(t^{3}-6t^{2})^{2}} \\ v=A \sqrt{t^{2}+t^{6}-12t^{5}+36t^{4}} \\ v=At \sqrt{t^{4}-12t^{3}+36t^{2}+1}

Answer: At√(t⁴ - 12t³ + 36t² + 1)
3 0
3 years ago
A material that can easily flow is called a
murzikaleks [220]
A material that can easily flow is called a...

A. Fluid.
3 0
3 years ago
Read 2 more answers
The concentration of Biochemical Oxygen Demand (BOD) in a river just downstream of a wastewater treatment plant’s effluent pipe
shtirl [24]

Answer:

The BOD concentration 50 km downstream when the velocity of the river is 15 km/day is 63.5 mg/L

Explanation:

Let the initial concentration of the BOD = C₀

Concentration of BOD at any time or point = C

dC/dt = - KC

∫ dC/C = -k ∫ dt

Integrating the left hand side from C₀ to C and the right hand side from 0 to t

In (C/C₀) = -kt + b (b = constant of integration)

At t = 0, C = C₀

In 1 = 0 + b

b = 0

In (C/C₀) = - kt

(C/C₀) = e⁻ᵏᵗ

C = C₀ e⁻ᵏᵗ

C₀ = 75 mg/L

k = 0.05 /day

C = 75 e⁻⁰•⁰⁵ᵗ

So, we need the BOD concentration 50 km downstream when the velocity of the river is 15 km/day

We calculate how many days it takes the river to reach 50 km downstream

Velocity = (displacement/time)

15 = 50/t

t = 50/15 = 3.3333 days

So, we need the C that corresponds to t = 3.3333 days

C = 75 e⁻⁰•⁰⁵ᵗ

0.05 t = 0.05 × 3.333 = 0.167

C = 75 e⁻⁰•¹⁶⁷

C = 63.5 mg/L

5 0
3 years ago
1. How far does a skydiver fall
GREYUIT [131]

Free fall without air resistance:

g=9.81 m/s²

t=235 s

h=?

h=0.5*g*t²

h=0.5*9.81*235²

h=270879m =270 km

5 0
3 years ago
Calculate the applied force to the piston with a 12cm radius required to elevate a weight of 2.0X104N by the piston with a 36cm
Alex

Answer:

Option D is the correct answer.

Explanation:

Refer the figure given.

By Pascal's principle we have

            \frac{F_1}{A_1}=\frac{F_2}{A_2}

F2 = 2 x 10⁴ N

A_1=\frac{\pi\times (12\times 10^{-3})^2}{4}=1.13\times 10^{-4}m^2\\\\A_2=\frac{\pi\times (36\times 10^{-3})^2}{4}=1.02\times 10^{-3}m^2

Substituting

      \frac{F_1}{1.13\times 10^{-4}}=\frac{2\times 10^4}{1.02\times 10^{-3}}\\\\F_1=2.22\times 10^3N

Option D is the correct answer.

6 0
3 years ago
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