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3 years ago

Balanced equations account for the conservation of mass.

Physics

2 answers:

marusya05 [52]3 years ago

7 0

Answer:

True

Explanation:

A balanced equation demonstrates the conservation of mass by having the same number of each type of atom on both sides of the arrow

uranmaximum [27]3 years ago

6 0

Answer:

fff

Explanation:

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Which of the following is a scalar? centripetal force weight speed acceleration

choli [55]

Scalar is a quantity such as mass or length that is completely determined by its own magnitude and has no direction. Therefore, your answer is Speed.

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3 years ago

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Mechanical waves are created when a source of energy causes a medium to ?

garik1379 [7]

A mechanical wave is created when a source of energy causes a vibration to travel through a medium

And yeah lol
A mechanical wave is a disturbance in matter that carries energy from one place to another :)

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4 years ago

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Can someone please help me with these physics problems? I just don’t even know where to start.

KIM [24]

for the block of mass 5 kg normal force is given as

$F_n = mg$

$F_n = 5*9.8 = 49 N$

friction force is given as

$F_f = \mu F_n$

$F_f = 0.1*49 = 4.9 N$

Net force is given as

$F_{net} = ma$

$F_{net} = 5*2 = 10 N$

now we know that

$F_{net} = F_{app} - F_f$

$10 = F_{app} - 4.9$

$F_{app} = 14.9 N$

Normal force is given as

$F_n = mg$

$F_n = 6*9.8$

$F_n = 58.8 N$

now we know that

$F_{net} = F_{app} - F_f$

$F_{net} = 0$

as object moves with constant velocity

$F_{app} = F_f = 15 N$

now for coefficient of friction we can use

$F_f = \mu F_n$

$15 = \mu * 58.8$

$\mu = 0.255$

net force upwards is given as

$F = 1.2 * 10^{-4} N$

mass is given as

$m = 7 * 10^{-5} kg$

now as per newton's law we can say

$F = ma$

$1.2 * 10^{-4} = 7 * 10^{-5} * a$

$a = 1.71 m/s^2$

As we know that when block is sliding on rough surface

part a)

net force = applied force - frictional force

$F_{net} = F_{app} - F_f$

$ma = F_{app} - F_f$

$5*6 = 40 - F_{f}$

$F_f = 40 - 30 = 10 N$

part b)

for coefficient of friction we can use

$F_f = \mu F_n$

$10 = \mu * F_n$

here normal force is given as

$F_n = mg = 5*9.8 = 49 N$

now we have

$\mu = \frac{10}{49} = 0.204$

if an object is initially at rest and moves 20 m in 5 s

so we can use kinematics to find out the acceleration

$d = v_i*t + \frac{1}{2}at^2$

$20 = 0 + \frac{1}{2}a(5^2)$

$a = 1.6 m/s^2$

now net force is given as

$F_{net} = ma$

$F_{net} = 10*1.6 = 16 N$

an object travelling with speed 25 m/s comes to stop in 1.5 s

so here acceleration of object is given as

$a = \frac{v_f - v_i}{t}$

$a = \frac{0 - 25}{1.5} = -16.67 m/s^2$

now the force is gievn as

$F = ma$

$F = 5*16.67 = 83.3 N$

3 0

4 years ago

A museum sets up a display of fluorescent minerals. Which best describes how electromagnetic waves can be used to enhance the di

belka [17]

Answer:

Explanation:

Ultraviolet light shining on the minerals will cause them to give off visible light.

8 0

3 years ago

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Chris and Sue are wearing harnesses and are hanging from the ceiling by means of ropes attached to them. They are face to face a

Setler [38]

Answer:

h = 0.288m

Explanation:

Assume

$v_1$ = Speed of Sue

$v_2$ = Speed of Chris immediately after the push

Sue's KE = $\frac{1}{2} mv_1\ ^2 = 26 v_1 \ ^2$

now she swings this is converted into gravitation at PE of

mg n = 52 × 9.8 × 0.65

= 331.24

$26v_{1}\ ^2$ = 331.24

So, $v_1 = 3.569$

They started at rest by conservation of momentum in case of push off the magnitude of sue momentum and it is equal to the magnitude of Chris momentum in the opposite or inverse direction

$m_1v_1 = m_2v_2$

$52 \times 3.569 = 78 \times v_2$

$v_2 = 2.380$

Chris kt = $\frac{1}{2} \times 78 \times 2.380^2$

= 220.827

220.827 = mgh

So, h = 0.288m

3 0

3 years ago