-- The object's weight is different on each planet, while it is
apparently weightless during the trips in between.
-- On some if not all of the three planets, the object needs to be
surrounded by protection from heat, cold, poisonous gases, or
solar radiation.
-- If the object is any kind of life form, then its circadian rhythm is
all screwed up, and it is having trouble sleeping.
-- The object has accumulated a huge balance of frequent flier miles.
Answer:
α = 3.59 [rad/s^2]]
Explanation:
First we have to convert the values of the angular speeds of revolutions per minute to radians on second.
wf = final angular velocity = 460 [rpm]
wo= initial velocity = 48 [rpm]
t = time = 12 [s]
![460 [\frac{rev}{min}]* [\frac{2\pi rad}{1 rev} ]*[\frac{1min}{60seg} ] = 48.17[\frac{rad}{s} ]\\48 [\frac{rev}{min}]* [\frac{2\pi rad}{1 rev} ]*[\frac{1min}{60seg} ] = 5.02[\frac{rad}{s} ]](https://tex.z-dn.net/?f=460%20%5B%5Cfrac%7Brev%7D%7Bmin%7D%5D%2A%20%5B%5Cfrac%7B2%5Cpi%20rad%7D%7B1%20rev%7D%20%5D%2A%5B%5Cfrac%7B1min%7D%7B60seg%7D%20%5D%20%3D%2048.17%5B%5Cfrac%7Brad%7D%7Bs%7D%20%5D%5C%5C48%20%5B%5Cfrac%7Brev%7D%7Bmin%7D%5D%2A%20%5B%5Cfrac%7B2%5Cpi%20rad%7D%7B1%20rev%7D%20%5D%2A%5B%5Cfrac%7B1min%7D%7B60seg%7D%20%5D%20%3D%205.02%5B%5Cfrac%7Brad%7D%7Bs%7D%20%5D)
now we can replace, in the following equation:
![w_{o}=w_{i} +\alpha *t\\where:\\\alpha = angular acceleration [rad/s^{2}]\\replacing:\\\alpha =\frac{w_{o} -w_{i} }{t} \\\alpha alpha =\frac{48.17-5.02 }{12} \\\alpha =3.59[\frac{rad}{s^{2} } ]](https://tex.z-dn.net/?f=w_%7Bo%7D%3Dw_%7Bi%7D%20%2B%5Calpha%20%20%2At%5C%5Cwhere%3A%5C%5C%5Calpha%20%3D%20angular%20acceleration%20%5Brad%2Fs%5E%7B2%7D%5D%5C%5Creplacing%3A%5C%5C%5Calpha%20%3D%5Cfrac%7Bw_%7Bo%7D%20-w_%7Bi%7D%20%7D%7Bt%7D%20%5C%5C%5Calpha%20alpha%20%3D%5Cfrac%7B48.17-5.02%20%7D%7B12%7D%20%5C%5C%5Calpha%20%3D3.59%5B%5Cfrac%7Brad%7D%7Bs%5E%7B2%7D%20%7D%20%5D)
All of these are necassary for photosynthesis. So your answer would be all of the above.
Answer:
The correct answer is
a) 1, 2, 3
Explanation:
In rolling down an inclined plane, the potential energy is Transferred to both linear and rotational kinetic energy thus
PE = KE or mgh = 1/2×m×v² + 1/2×I×ω²
The transformation equation fom potential to kinetic energy is =
m×g×h = 
= 
= 
=
Therefore the order is with increasing rotational kinetic energy hence
the first is the sphere 1 followed by the disc 2 then the hoop 3
the correct order is a, 1, 2, 3
(a) The frequency the blackbird hears is 461.15 Hz.
(b) The frequency the blackbird hears after the eagle passes the blackbird is 422.35 Hz.
Given that, velocity of the eagle v₁ = 31 m/s
Frequency of the eagle F₁ = 440 Hz
Velocity of the blackbird v₂ = 16 m/s
Speed of sound v = 343 m/s
(a) The equation for frequency is given as F = f₀ (v-v₂)/(v-v₁)
F = 440 * (343-16)/(343-31) = 440 * 327/312 = 461.15 Hz
(b) The equation for frequency is given as F = f₀ (v+v₂)/(v+v₁)
F = 440 * (343+16)/(343+31) = 440 *359/374 = 422.35 Hz
To know more about frequency:
brainly.com/question/24261941
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