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Advocard [28]
4 years ago
13

Octylphenol ethoxylate is a detergent that is commonly used in chemistry laboratories. It is a thick, yellowish liquid. A chemis

t dissolves a small amount of octylphenol ethoxylate in a liter of benzene, an organic liquid, then adds a small amount of toluene, another organic liquid. Identify each component of the solution as a solute or a solvent.
Benzene is a

a) solute.

b) solvent.


Toluene is a

a) solute.

b) solvent.


Octylphenol ethoxylate is a

a) solute.

b)solvent.

the answer on edge2020 is solvent, solute, solute
Chemistry
1 answer:
Trava [24]4 years ago
3 0

Answer:

is solvent, solute, solute

Explanation:

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What is the molarity of a solution that contains 17g of NH₃ in 0.50L of solution?
erastovalidia [21]

Explanation:

Because molarity is mol/L, we'll have to convert 17g to mol.

After obtaining the mol, we'll divide that by the volume to obtain Molarity.

3 0
3 years ago
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calculate the water potential of a solution of 0.15m sucrose. the solution is at standard temperature.
Mrac [35]

Answer:

The water potential of a solution of 0.15 M sucrose solution is -3.406 bar.

Explanation:

Water potential = Pressure potential + solute potential

P_w=P_p+P_s

P_w=P_p+(-iCRT)

We have :

C = 0.15 M, T = 273.15 K

i = 1

The water potential of a solution of 0.15 m sucrose= P_w

P_p=0 bar (At standard temperature)

P_s=-iCRT=-\times 1\times 8.314\times 10^{-2}bar L/mol K\times 273.15 K=-3.406 bar

P_w=0 bar+(-3.406 ) bar

The water potential of a solution of 0.15 M sucrose solution is -3.406 bar.

7 0
3 years ago
What is the volume of 1.60 grams of O2 gas at STP? (5 points)
tiny-mole [99]

Answer:

  • <u><em>1.12 liters</em></u>

Explanation:

<u>Calculating number of moles</u>

  • Molar mass of O₂ = 32 g
  • n = Given weight / Molar mass
  • n = 1.6/32
  • n = 0.05 moles

<u>At STP</u>

  • One mole of O₂ occupies 22.4 L
  • Therefore, 0.05 moles will occupy :
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5 0
2 years ago
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A solution of acetic acid has a pH of 3.45. What is the concentration of acetic acid in this solution? Ka for CH3COOH is 1.8×10-
Serjik [45]

Answer:

0.007 M

Explanation:

pH is defined as the negative logarithm of the concentration of hydrogen ions.

Thus,  

pH = - log [H⁺]

The expression of the pH of the calculation of weak acid is:-

pH=-log(\sqrt{k_a\times C})

Where, C is the concentration = ?

Given, pH = 3.45

So, for CH_3COOH, K_a=1.8\times 10^{-5}

3.45=-log(\sqrt{1.8\times 10^{-5}\times C})

\log _{10}\left(\sqrt{1.8\cdot \:10^{-5}C}\right)=-3.45

C = 0.007 M

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3 years ago
Use the molar bond enthalpy data in the table to estimate the value of Δ∘rxn
MakcuM [25]

Answer:

ΔH°rxn = - 433.1 KJ/mol

Explanation:

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⇒ ΔH°rxn = 4ΔH°HCl(g) + ΔH°CCl4(g) - 4ΔH°Cl2(g) - ΔH°CH4(g)

∴ ΔH°Cl2(g) = 0 KJ/mol.....pure element in its reference state

∴ ΔH°CCl4(g) = - 138.7 KJ/mol

∴ ΔH°HCl(g) = - 92.3 KJ/mol

∴ ΔH°CH4(g) = - 74.8 KJ/mol

⇒ ΔH°rxn = 4(- 92.3 KJ/mol) + (- 138.7 KJ/mol) - 4(0 KJ/mol) - (- 74.8 KJ/mol)

⇒  ΔH°rxn = - 369.2 KJ/mol - 138.7 KJ/mol - 0 KJ/mol + 74.8 KJ/mol

⇒ ΔH°rxn = - 433.1 KJ/mol

4 0
3 years ago
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