Answer:
nacl with water
they are capable of conducting electricity
Answer:
Neutralization reactions occur when two reactants, an acid and a base, combine to form the products salt and water.
100ml volume of 0.0150m hcl solution is requires to titrate 150ml of a 0.0100m caoh2 solution.
Dilution is a solution of decreasing the concentration of a solute in the solution by adding more solvent to the solution. We can use the expression for dilute formula,
C1 V1 =C2 V2
where C1 is the initial concentration,C2 is the final concentration,V1 is the initial volume and V2 is the final volume. Here given, volume of 0.0150M(C1) HCL solution is required to titrate 150ml(V2) of a 0.0100M(C1) Caoh2 solution.
While diluting a solution from a high concentration substance to a low concentration substance we always use the formula of dilution.so, putting all value give in the expression we get the volume of the final concentration.
V1= C2 V2/ C1
= 0.0100m . 150ml /0.0150M
= 100ml
The volume of the hcl solution is 100ml.
To learn more about dilution formula please visit:
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Answer:
The vernal equinox occurs on March 20 or March 21 each year and signals the start of spring in the Northern Hemisphere (and fall in the Southern Hemisphere). The Earth tilts at an angle of 23.5 degrees on its axis relative to its plane of orbit around the sun. My source is history.com A, i think
Explanation:
hope this hlps
<span>Molar mass is the mass of
one mole of a substance, it can be a chemical element or a compound. It is a
characteristic of each pure substance. We calculate it by adding up all of the masses of the atoms involved in the compound. We calculate as follows:
atomic mass total mass
C 17 12.01 g/mol 204.17 g/mol
H 19 1.01 g/mol 19.19 g/mol
N 1 14.00 g/mol 14.00 g/mol
O 3 16.00 g/mol 48.00 g/mol
------------------------------------------------------------
Molar mass = 285.36 g/mol
</span><span>What is the mass of 6.02 x 10^24 molecules of morphine?
</span>6.02 x 10^24 molecules ( 1 mol / 6.02x10^23 molecules) ( 285.36 g/mol) = 2853.6 g morphine
