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zhannawk [14.2K]
2 years ago
9

Which of these best explains the formation of deep ocean currents

Chemistry
1 answer:
timurjin [86]2 years ago
5 0

Answer:

if you could copy and paste the text or a picture of the options, i'd be more than happy to answer

Explanation:

:)

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PLEASE HELP!!!The measurement of how fast an object moves over a certain amount of time.
ad-work [718]
1- <span>Acceleration
2- </span><span>Velocity
</span>3- <span>25 mph
4- </span><span>50 mph east
5- </span><span>Speed
6- 0
7- </span><span>It decreases
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3 0
3 years ago
Read 2 more answers
(b) A compound X contains carbon, hydrogen and oxygen only
faust18 [17]

Answer:

C2H4O

Explanation:

C H O

54.54/12 9.09/1 36.37/16

4.545 9.09 2.27

4.545/2.27 9.09/2.27 2.27/2.27

2.00 4.00 1

Empirical formula is C2H4O

3 0
3 years ago
Is the process of sediment being placed in a new location.
PSYCHO15rus [73]

Answer:

Deposition

Explanation:

Deposition is the process of sediment being placed in a new location.

6 0
3 years ago
CO(g)+2H2(g)⇌CH3OH(g) A reaction mixture in a 5.23-L flask at a certain temperature initially contains 27.2 g CO and 2.36 g H2.
irga5000 [103]

Answer: 5.70M

Explanation:

Molar mass of CO = 28.01 g/mol

Molar mass of H2 = 2.02 g/mol

Molar mass of CH3OH = 32.05 g/mol.

To determine the amount of each compound in the reaction mixture we use the formula.

Amount in mol = reacting mass/molar mass.

Inputing the given values we have,

26.6 g CO x (1 mol / 28.01 g ) = 0.9496608354 mol of CO.

To calculate the concentration of CO we use C=n/v, where n=amount and v= volume of CO.

Inputing the values in the formula

[CO] = 0.9496608354 mol CO / 5.23 L = 0.18158 M CO

Repeating thesame procedure for H

Amount of H=2.36 g H2 x ( 1 mol / 2.02 g ) = 1.168316832 mol of H2

Concentration of H2 in the mixture

[H2] = 1.168316832 mol H2 / 5.23 L = 0.223388 M of H2

Amount of CH3OH is determine similarly using rmass/molar mass

8.66 CH3OH x (1 mol / 32.05 g ) = 0.2702028081 mol of CH3OH

Concentration of

[CH3OH] = 0.2702028081 mol CH3OH/ 5.23 L = 0.051664 M CH3OH

Now equilibrium constant is determined by

Kc = [CH3OH] / [CO] [H2]^2

=0.051664/0.18158×0.223388×0.223388.

=5.70

7 0
3 years ago
Considere un elemento "X" que posee como valencias 2, 4 y 6. En su nomenclatura tradicional, considerando la valencia cuatro, es
Ierofanga [76]

Answer:

"ite"

Explanation:

Se sabe que los elementos del grupo 16 de la tabla prioritaria muestran estados de oxidación o valencias de 2,4 y 6 respectivamente, dependiendo del compuesto formado.

Por ejemplo, el azufre forma los siguientes compuestos;

sulfato de sodio (el azufre tiene una valencia de 6)

Sulfito de sodio (el azufre tiene una valencia de 4)

Sulfuro de sodio (el azufre tiene una valencia de 2)

Por lo tanto, en compuestos en los que exhiben una valencia de 4, la terminación común es "ite"

8 0
3 years ago
Read 2 more answers
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