All categories

4 years ago

A 2kg picture frame sits on a shelf at a height of 0.5 m

Physics

1 answer:

mote1985 [20]4 years ago

5 0

Can u please complete the question and make it clear

You might be interested in

_____ help by supporting the plant and holding the leaves up to the light.

Semenov [28]

The answer is the stem.

7 0

3 years ago

Read 2 more answers

Saturn has an orbital period of 29.46 years. In two or more complete sentences, explain how to calculate the average distance fr

soldi70 [24.7K]

$Given:\\T=29.46y\approx 9.29\cdot 10^8s\\M_S\approx2.0\cdot 10^{30}kg\\G=6.67\cdot 10^{-11} \frac{m^3}{kg\cdot s^2} \\\\Find:\\R=?\\\\Solution:\\\\F_g= G\frac{mM_s}{R^2} \\\\F_c= \frac{mv^2}{R} \\\\F_g=F_c\\\\G\frac{mM_s}{R^2}=\frac{mv^2}{R} \Rightarrow G\frac{M_s}{R^2}=\frac{v^2}{R}\\\\v=\omega r\\\\G\frac{M_s}{R^2}= \frac{\omega^2R^2}{R}\Rightarrow G\frac{M_s}{R^2}=\omega^2R \\\\\omega= \frac{2 \pi }{T} \\\\G\frac{M_s}{R^3}= \frac{4 \pi ^2}{T^2}$

$GM_ST^2=4 \pi ^2R^3\Rightarrow R= \sqrt[3]{ \frac{GM_ST^2}{4 \pi ^2} }\\\\\\R= \sqrt[3]{ \frac{6.67\cdot 10^{-11} \frac{m^3}{kg\cdot s^2}\cdot2.0\cdot 10^{30}kg( 9.29\cdot 10^8s)^2}{4\cdot 3.14^2} } \approx 1.42\cdot 10^{12}m$

3 0

3 years ago

Plane-polarized light is incident on a single polarizing disk, withthe direction of E0 parallel to thedirection of the transmiss

Alenkinab [10]

Answer;

Cos²စ= I/Io

A. Cos²စ = 1/2.2

Cosစ= √1/2.2

စ = cos^-1 0.68

= 47.2°

Cosစ = √1/5.2

စ = ,cos^-1 0.4385

= 64°

Cosစ = √1/12

စ = cos^-1 0.2886

= 73.2°

6 0

3 years ago

55N of force are applied onto a table, but the force of friction is 8N. What is the net force acting on the table? Please explai

nirvana33 [79]

Answer:

get a tutor or something to help man

Explanation:

8 0

3 years ago

A force of 100 N acts upward. Resolve this force into 2 components; one that acts 30º north of west and one that acts 60º north

GrogVix [38]

To resolve these forces we have to make use of the sines and cosines.

To resolve this force in 30 degree north of west, the answer will be

100*sin(30)

The answer will be 50N

Now to resolve the force acting 60 degree north of east

100* cos(60)

The answer will be 50N.

This also adds to the total force acting that is 50+50=100N. This is the way forces are resolved according to their specified angles.

5 0

3 years ago