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viva [34]
2 years ago
6

Which of thes is a property of a substance that is composed of atoms that are held together by ionic bonds?

Chemistry
1 answer:
Svetlanka [38]2 years ago
8 0

Answer: D) It conducts electricity when it is dissolved in water

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What is units we used for measuring the radon gas?
lisabon 2012 [21]

Answer:

Bq/m3 (becquerels per cubic meter) or pCi/l (picocuries per litre)

Explanation:

The unit of the International System of Units identified to measure radioactive activity is Becquerelio (Bq) and equivalent to one decay per second.

The Curio (Ci) is also a radioactivity unit, which is still being used in some countries. It owes its name to chemists and chemists Pierre and Marie Curie.

It represents the amount of material in which 3.7 × 1010 atoms per second, or 3.7 × 1010 nuclear decays per second, which is roughly the activity of 1 g of 226Ra (isotope of the chemical chemical element).

The equivalence between the two is:

1Ci= 3,7 × 1010Bq

The specific radioactive activity of a radioactive gas such as radon gas is measured per unit volume and measured in Bq/m3 or pCi/l.

In this case the equivalence is:

1pCi/l= 37Bq/m3

6 0
4 years ago
Orbital structure of sodium?
algol13

Answer:

na.

sodium

11( 2,81,)

pls Mark me as brainlest

5 0
3 years ago
PLS HELP FOR BRA.INLIEST
snow_tiger [21]
C bc the answer is 75
3 0
3 years ago
Read 2 more answers
When coal is burned, _____ energy is being converted to _____ energy.
LiRa [457]
I am pretty sure the answer is D
4 0
3 years ago
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What is the wavelength in picometers for an electron with 360 eV of kinetic energy?
Rom4ik [11]

Answer:

Wavelength = 64.635 pm

Explanation:

The expression for the deBroglie wavelength and kinetic energy is:

\lambda=\frac {h}{\sqrt{2\times m\times K.E.}}

Where,  

\lambda is the deBroglie wavelength  

h is Plank's constant having value 6.626\times 10^{-34}\ Js

m is the mass of electron having value 9.11\times 10^{-31}\ kg

K.E. is the kinetic energy of the electron.

Given, K.E. = 360 eV

Energy in eV can be converted to energy in J as:

1 eV = 1.6022 × 10⁻¹⁹ J

So, K.E. = 360\times 1.6022\times 10^{-19}\ J=5.76792\times 10^{-17}\ J

Applying in the equation as:

\lambda=\frac {h}{\sqrt{2\times m\times K.E.}}

\lambda=\frac{6.626\times 10^{-34}}{\sqrt {{2\times 9.11\times 10^{-31}\times 5.76792\times 10^{-17}}}}\ m

\lambda=\frac{10^{-34}\times \:6.626}{\sqrt{10^{-48}\times \:105.0915024}}\ m

\lambda=6.4635\times 10^{-11}\ m

Also, 1 m = 10¹² pm

<u>So, Wavelength = 64.635 pm</u>

4 0
4 years ago
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