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pashok25 [27]
3 years ago
7

How can you identify a chloride from an iodide solution using the silver nitrate and sodium thiosulfate test?

Chemistry
1 answer:
scoundrel [369]3 years ago
7 0
For the silver nitrate test, the solution is added first with nitric acid. This test is to determine halide ions. When silver nitrate is added to the solution, the color of the precipitate would indicate the identity of the ion. For chloride ions, the precipitate is white.

For the sodium thiosulfate test, chlorine is treated with Ki solution which turns brown. When it is titrated with sodium thiosulfate solution, the brown turns yellow upon which, starch is added. It forms a complex which appears as dark blue. Upon adding more titrant, it reaches the endpoint where the blue turns colorless.
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A student notices that after two chemicals are mixed together the temperature of the mixture is higher than the temperature of t
swat32

Answer: exothermic

EXPLANATION: any process in which heat energy is released is called an exothermic process. For example burning of wood produces heat, so combustion of wood is an exothermic process.

When chemicals were not mixed they were at room temperature and when we mix them exothermic reaction took place and heat was released which raised the temperature of mixture.

7 0
3 years ago
Which one is it ? I need help
Lostsunrise [7]
It would 3 because if you read it tells you the answer
8 0
2 years ago
Read 2 more answers
Plz help :(
ziro4ka [17]
<h2>Answer:0.5 moles,1 mole</h2>

Explanation:

Sr(NO_{3})_{2} is readily soluble in water.

Sr(NO_{3})_{2} dissolves in water to give Sr^{2+} ions and NO_{3}^{-} ions.

The reaction is

Sr(NO_{3})_{2}→Sr^{2+}+2NO_{3}^{-}

So,1 mole of Sr(NO_{3})_{2} gives 1 mole of Sr^{2+} and 2 moles of NO_{3}^{-}.

So,0.5 moles of Sr(NO_{3})_{2} gives 0.5 moles of Sr^{2+} and 1 mole of NO_{3}^{-}.

5 0
3 years ago
DIRECTION: Supply the missing information about the scientist listed in the graphic
e-lub [12.9K]

Answer:

The missing information or their role in the discovery of the cell is as follows:

Robert Hooke: He was the first scientist to called cells to tiny box-like cavities he saw in cork and illustrated as cells.

A. Leeuwenhoek: he was a microscopist and microbiologist who used microscopes and observed many other living cells. He called animalcules to these single-cell living organisms later used to prove that cells are the fundamental unit of life.

Schwann and Schleiden:  They presented the theory that suggested that the cells are basic building blocks of all living things.

Virchow: He observed that the cell dividing and come from pre-existing cells.

6 0
2 years ago
Determine the free energy(ΔG) from the standard cell potential (Ecell0 ) for the reaction:2ClO2-(aq)+Cl2(g)→2ClO2(g)+ 2Cl-(aq)wh
Dima020 [189]

<u>Answer:</u> The \Delta G^o for the given reaction is -7.84\times 10^4J

<u>Explanation:</u>

For the given chemical reaction:

2ClO_2^-(aq.)+Cl_2(g)\rightarrow 2ClO_2(g)+2Cl^-(aq.)

Half reactions for the given cell follows:

<u>Oxidation half reaction:</u> ClO_2^-\rightarrow ClO_2+e^-;E^o_{ClO_2^-/ClO_2}=0.954V  ( × 2)

<u>Reduction half reaction:</u> Cl_2+2e^-\rightarrow 2Cl(g);E^o_{Cl_2/2Cl^-}=1.36V

Oxidation reaction occurs at anode and reduction reaction occurs at cathode.

To calculate the E^o_{cell} of the reaction, we use the equation:

E^o_{cell}=E^o_{cathode}-E^o_{anode}

Putting values in above equation, we get:

E^o_{cell}=1.36-(0.954)=0.406V

To calculate standard Gibbs free energy, we use the equation:

\Delta G^o=-nFE^o_{cell}

Where,

n = number of electrons transferred = 2

F = Faradays constant = 96500 C

E^o_{cell} = standard cell potential = 0.406 V

Putting values in above equation, we get:

\Delta G^o=-2\times 96500\times 0.406=-78358J=-7.84\times 10^4J

Hence, the \Delta G^o for the given reaction is -7.84\times 10^4J

4 0
3 years ago
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