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pashok25 [27]
3 years ago
7

How can you identify a chloride from an iodide solution using the silver nitrate and sodium thiosulfate test?

Chemistry
1 answer:
scoundrel [369]3 years ago
7 0
For the silver nitrate test, the solution is added first with nitric acid. This test is to determine halide ions. When silver nitrate is added to the solution, the color of the precipitate would indicate the identity of the ion. For chloride ions, the precipitate is white.

For the sodium thiosulfate test, chlorine is treated with Ki solution which turns brown. When it is titrated with sodium thiosulfate solution, the brown turns yellow upon which, starch is added. It forms a complex which appears as dark blue. Upon adding more titrant, it reaches the endpoint where the blue turns colorless.
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If 3.45 grams of Mg are burned how many grams of MgO are produced
coldgirl [10]
  The  number   of grams  of Mgo   that  are  produced  is calculated  as follows
  calculate  the  moles  of  Mg  used

that  is  moles =mass/molar  mass
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4 0
2 years ago
Read 2 more answers
A 13.5 g sample of an aqueous solution of nitric acid contains an unknown amount of the acid. If 23.5 mL of 0.434 M barium hydro
zavuch27 [327]

The percent by mass of nitric acid in the mixture is 3.36 %

2 HNO3 + Ba(OH)2 --->Ba(NO3)2 + 2H2O

so 1 mole Ba(OH)2 neutralizes 2 mol HNO3

moles of Ba(OH)2 present = molarity of base* volume of base

= 0.229 M * 15.6 ml

= 3.5724 milli mols

mols of HNO3 neutralized = 2* mols of Ca(OH)2 used

= 2* 3.5724 milli mols = 7.1448 x10^-3 mols

molar mass of HNO3 = 63.01 g/mol

mass of HNO3 present = molar mass * mols of HNO3

= 63.01 g/mol * 7.1448 x10^-3 mols

=0.4502 g

mass of sample = 13.4 g

mass % = mass of HNO3/mass of sample * 100

= 0.4502/13.4 *100

= 3.36 %

Nitric acid is a colorless, fuming, and distinctly corrosive liquid that could be a not unusual laboratory reagent and an important commercial chemical for the manufacture of fertilizers and explosives.

Learn more about Nitric acid here: brainly.com/question/22698468

#SPJ4

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