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larisa86 [58]
2 years ago
7

2 NaOH (s) + CO2(g) → Na2CO3 (s) + H20 (I) How many grams of water can be produced with 1.85 moles of NaOH​

Chemistry
2 answers:
maks197457 [2]2 years ago
7 0

Answer:

<em><u>16.65 grams</u></em> of water can be produced with 1.85 moles of NaOH.

Explanation:

Mole ratio of NaOH to H2O = 2 : 1

Number of moles of water = (1/2)×1.85= 0.925 moles

Molar mass of water (H2O) = 18g/mol

Mass of the right water = 18g/mol×0.925 mol=16.65 grams

Romashka [77]2 years ago
4 0

Explanation:

Mole ratio of NaOH to H2O = 2 : 1

Moles of H2O = 1.85mol * (1/2) = 0.925mol.

Mass of H2O = 0.925mol * (18g/mol) = 16.65g.

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Explanation:

Since HF is a weak acid, the use of an ICE table is required to find the pH. The question gives us the concentration of the HF.

HF+H2O⇌H3O++F−HF+H2O⇌H3O++F−

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Writing the information from the ICE Table in Equation form yields

6.6×10−4=x20.3−x6.6×10−4=x20.3−x

Manipulating the equation to get everything on one side yields

0=x2+6.6×10−4x−1.98×10−40=x2+6.6×10−4x−1.98×10−4

Now this information is plugged into the quadratic formula to give

x=−6.6×10−4±(6.6×10−4)2−4(1)(−1.98×10−4)−−−−−−−−−−−−−−−−−−−−−−−−−−−−√2x=−6.6×10−4±(6.6×10−4)2−4(1)(−1.98×10−4)2

The quadratic formula yields that x=0.013745 and x=-0.014405

However we can rule out x=-0.014405 because there cannot be negative concentrations. Therefore to get the pH we plug the concentration of H3O+ into the equation pH=-log(0.013745) and get pH=1.86

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