The new volume of the gas that has an initial pressure of 5.6 x 10⁵ Pa is 5.7L. Details about volume of the gas can be found below.
<h3>How to calculate volume?</h3>
The volume of a gas can be calculated using the Boyle's law equation as follows:
P1V1 = P2V2
Where;
- P1 = initial pressure
- P2 = final pressure
- V1 = initial volume
- V2 = final volume
1.53 × 5.6 × 10⁵ = 1.5 × 10⁵ × V2
8.568 × 10⁵ = 1.5 × 10⁵V2
V2 = 8.57 × 10⁵ ÷ 1.5 × 10⁵
V2 = 5.7L
Therefore, the new volume of the gas that has an initial pressure of 5.6 x 10⁵ Pa is 5.7L.
Learn more about volume at: brainly.com/question/12357202
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The answer is C because you don’t have to worry about the number in front of the decimal unless it is something greater than zero. A- Doesn’t have there sig figs. B- The zero after the 5 doesn’t change it. D- The three at the end doesn’t matter because it does not round it up.
Answer: By understanding conversion factors and how they are related to each other
Explanation:
Dimensional Analysis is a step by step approach to solving problems in Physics, Chemistry , and Mathematics. It involves having a clear knowledge and understanding to be able to convert a given unit to another in the same dimension using conversion factors and knowing how they are related to each other.
For instance, In Chemistry, we want to Convert 120mL to L.(note that ml stands for millilitres and ;L stands for litres)
Or first approach will be to write out the conversion factor related to our problem which is
1000ml =1L
such that 120ml = (we cross multiply))
giving us 120ml x 1L/1000ml =0.12L
This same process is applied to convert any type of dimensional analysis problems be it physics or mathematics.
Mass of CO₂ evolved : 0.108 g
<h3>Further explanation</h3>
Given
1.205g sample, 36% MgCO3 and 44% K2CO3
Required
mass of CO2
Solution
0.36 x 1.205 g=0.4338 g
mass C in MgCO₃(MW MgCO₃=84 g/mol, Ar C = 12/gmol)
= (12/84) x 0.4338
= 0.062 g
0.44 x 1.205 g = 0.5302 g
Mass C in K₂CO₃(MW=138 g/mol) :
= (12/138) x 0.5302
= 0.046 g
Total mass Of CO₂ :
= 0.062 + 0.046
= 0.108 g
