Answer:
a) 25.5 µH
b) 22.95 mV
Explanation:
Induced emf in a inductor is given by
E = L * di/dt, where
E is the voltage of the circuit
L is the inductance of the circuit
di/dt if the rate of inductance
A
So we have
0.0037 = L * 145
L = 0.0037 / 145
L = 0.0000255
L = 25.5 µH
B
i(t) = 225t²
Recall that
E = L * di/dt, so that
E = 25.5 µH * |225t²|
Differentiating with respect to t, we have
E = 25.5 * 2 * 225t
E = 25.5 * 450t
Solving for t = 2,we get
E = 25.5 * 450(2)
E = 25.5 * 900
E = 22950 µV or
E = 22.95 mV
Answer:
The electrons in oxygen are paired while in nitrogen, they are not.
Explanation:
To analyse this we start with writing out the ground state electronic configurations for both elements.
Oxygen: 1s²2s²2p4 meaning the p subshell has the following arrangement of electrons ↑↓ ↑ ↑
Nitrogen : 1s²2s²2p³ meaning the p subshell has the following arrangement of electrons ↑ ↑ ↑
Clearly the paired electron in oxygen will be experiencing repulsion from the electron it shares an orbital with causing it to be removed easily. The electrons in nitrogen are unpaired, each orbital is singly occupied
Answer:
The moon Phobos orbits Mars
(mass = 6.42 x 1023 kg) at a distance
of 9.38 x 106 m. What is its period of
orbit?
Explanation:
Answer: 27.9816 x 10^3 is the period of orbit
