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Zanzabum
3 years ago
6

If the mass of an object i if the mass of an object is 44 kg in its velocity is 10 m/s East how much kinetic energy

Physics
1 answer:
vampirchik [111]3 years ago
8 0
K=0.5 mu×u
K=2200J no matter the direction
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As the temperature increases the number of effective collisions between reacting particles in a chemical reaction
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Answer: option A) initially increases, then decreases.

Justification:

The increase of the rate of effective collisions among particles as the temperature increases is explained by the collision theory in virtue of the increase of the kinetic energy.

This is, as the temperature increase so the kinetic energy increase and the higher the kinetic energy the greater the number of collisions and the greater the chances that this energy overcome the activation energy (the energy needed to start the reaction).

Now, as the reaction progress the number of reactants particles naturally decrease (some of them have been converted into product) so this lower number of particles means lower concentration which means lower collisions and, thereafter, a decrease in the reaction rate.

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Explain Newton's third law in your own words.
Kazeer [188]
Newton's third law states "for every action, there is an equal and opposite reaction."

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3 years ago
A 1250 kg car, driving 7.39 m/s, runs into the back of a stationary 5380 kg truck. After the collision, the truck moves forward
Leno4ka [110]

Explanation:

Given that,

Mass of the car, m₁ = 1250 kg

Initial speed of the car, u₁ = 7.39 m/s

Mass of the truck, m₂ = 5380 kg

It is stationary, u₂ = 0

Final speed of the truck, v₂ = 2.3 m/s

Let v₁ is the final velocity of the car. Using the conservation of momentum as :

m_1u_1+m_2u_2=m_1v_1+m_2v_2

1250\times 7.39+5380\times 0=1250\times v_1+5380\times 2.3

v_1=-2.5\ m/s

So, the final velocity of the car is 2.5 m/s but in opposite direction. Hence, this is the required solution.

3 0
3 years ago
How much tension must a rope withstand if it is used to accelerate a 6526 kg car vertically upwards at 8.9 m/s^2?
ExtremeBDS [4]

Answer:

The value is T =  122036.2 \  N

Explanation:

From the question we are told that

     The mass of the car is  m  = 6526 \  kg

      The acceleration  is  a=  8.9 \  m/s^2

Generally the net force applied on the rope is mathematically represented as

          F_{net}   =  T -  W

Here W is the weight of the car which is evaluated as

         W =  m * g

=>      W =  6526  * 9.8

=>       W =  63954.8 \  N

Generally the net force can also be mathematically represented as

       F =  m * a

So

        m * a  =  T  -  63954.8

=>     6526  *  8.9 =  T  -  63954.8

=>      T =  122036.2 \  N

7 0
3 years ago
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