A chemical label should include: a product identifier, signal word, hazard statement, precautionary statement,pictorgrams and supplier information
Explanation:
The product identifier : positioned at the upper left end corner of the label gives the identity of the hazardous chemical by appropriate terms. i.e. the name and code
Signal word: The "Danger" and "WARNING" words. The former is used for a more severe hazard where as the former is for a less severe hazard
Hazard statement : gives a description of the nature and degree of hazard of the chemical
Precautionary statements : Put for workers and users on ways to minimize exposure and lower risks in event of contact with the harmful chemical
Supplier information : It has the chemical manufacturer details such as name, location and telephone number.
Pictograms : Normally symbols with red borders for visual illustration of the hazard chemical.
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Chemical labels : brainly.com/question/3115518
Keywords : chemical, labels
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Given:
Mass(m)=75kg
Height (h) =100m
v(velocity)=60m/s
a(g)=9.8m/s^2(since it is a free falling object)
Now we know that
v=u+at
We know that
Potential energy=mgh
Where m is the mass
g is the acceleration due to gravity
h is the height above the ground
Substituting the above values we get
Potential energy=75 x 9.8 x 100
=73500N
Now kinetic energy =1/2mv^2
Where m is the mass
v is the velocity
Kinetic energy= 1/2 (75x60 x 60)
Kinetic energy=135000N
Now mechanical energy=
Kinetic energy+ Potential energy
Substituting the values in the above formula we get
Mechanical energy= 73500+135000
=208500N
C6H14
Gaseous state
it's unsaturated hence gaseous
Answer:
132.9 cm
Explanation:
Data provided in the question:
Radius of the basll = 76 cm = 0.76 m
Side of the box = 200 cm = 2 m
Density of the ball and cube are equal
let the density be 'D'
Now,
Mass of ball, M = Volume × Density
= 
× D
= 
× D
= 1.838D
Mass of cube, m = L³ × D
= 2³ × D
= 8D
Thus,
center of mass, y = [ My₁ + my₂ ] ÷ [M + m]
here,
y₁ = center of mass of ball with respect to floor
as the center mass of sphere lies at the center of the sphere
= Length of cube + radius of sphere
= 2 + 0.76
= 2.76 m
y₂ = Center of mass of cube = 
= 1 m
Thus,
y = [ ( 1.838D × 2.76 ) + (8D × 1 ) ] ÷ [1.838D + 8D]
= 13.07288D ÷ 9.838D
= 1.329 m
or
= 132.9 cm
