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3 years ago

If you put a object in front of the mirror why does it appear the opposite way

1 answer:

4 0

It is because that is how mirrors work, they reflect light, and since we see objects because we are seeing the light these objects reflect, what is reflected back by the mirror is what we see.

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What is the mass of metal if it has a density of 12.459 hg/cm^3 and displaces 28.7cm^3 of water

natima [27]

Answer:

357.6g

Explanation:

Given parameters:

Density = 12.459g/cm³

Volume of metal = 28.7cm³

Unknown:

Mass of metal = ?

Solution:

The density of a substance is its mass per unit volume.

To find the mass;

Mass of metal = density x volume

Now insert the parameters and solve;

Mass of metal = 12.459 x 28.7 = 357.6g

7 0

3 years ago

Maximum current problem. If the current on your power supply exceeds 500 mA it can damage the supply. Suppose the supply is set

VikaD [51]

To solve this problem we will apply Ohm's law. The law establishes that the potential difference V that we apply between the ends of a given conductor is proportional to the intensity of the current I flowing through the said conductor. Ohm completed the law by introducing the notion of electrical resistance R. Mathematically it can be described as

$V = IR \rightarrow R = \frac{V}{I}$

Our values are

$I = 500mA = 0.5A$

$V = 37V$

Replacing,

$R = \frac{V}{I}$

$R = \frac{37}{0.5}$

$R = 74 \Omega$

Therefore the smallest resistance you can measure is $74 \Omega$

8 0

3 years ago

What is the term for the overall change in position?

mart [117]

That's "displacement". It only depends on the beginning and ending locations, and doesn't care about the route between them.

6 0

3 years ago

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This problem follows up on a discussion from lecture. A wind turbine with an efficiency of 45% for converting wind energy into e

Volgvan

Answer:

4.1 m

Explanation:

10 kW = 10000 W

20mi/h = 20*1.6 km/mi = 32 km/h = 32 * 1000 (m/km) *(1/3600) hr/s = 8.89 m/s

The power yielded by the wind turbine can be calculated using the following formula

$P = \frac{1}{2} \rho v^3 A C_p$

where $\rho = 1.2 kg/m^3$ is the air density, v = 8.89 m/s is the wind speed, A is the swept area and $C_p = 0.45$ is the efficiency

$10000 = 0.5 * 1.2 * 8.89^3 * A * 0.45$

$10000 = 190A$

$A = 10000 / 190 = 52.7 m^2$

The swept area is a circle with radius r being the blade length

$\pi r^2 = A = 52.7$

$r^2 = 52.7 / \pi = 16.79$

$r = \sqrt{16.79} = 4.1 m$

4 0

3 years ago

What is a transverse wave? How do the particles in the medium move in relation to the energy of the wave? Does this wave require

Pani-rosa [81]

A transverse wave is a wave where the particles in the medium move perpendicular (at right angles) to the direction of the source or its propagation (think of a snake slithering through grass) an example of a transverse wave could be a light wave. Light waves for instance don’t need a medium in order to propagate but transverse waves in general do need a medium.

4 0

3 years ago

Read 2 more answers