First of all the ethylamine is base so will be react with water to take the proton from the water (H⁺) , because water is amphoteric will react with bases as acid and acids as a base, so the water in this case will react as an acid and will gives the proton to the base.
In the picture you may see the chemical equation and the structure of the products.
First, you need to find:
One mole of
is equivalent to how many grams?
Well, for this you have to look up the periodic table. According to the periodic table:
The atomic mass of Calcium Ca = 40.078 g (See in group 2)
The atomic mass of <span>Chlorine Cl = 35.45 g (See in group 17)
</span>
As there are two atoms of Chlorine present in
, therefore, the atomic mass of
would be:
Atomic mass of
= Atomic mass of Ca + 2 * Atomic mass of Cl
Atomic mass of
= 40.078 + 2 * 35.45 = 110.978 g
Now,
110.978 g of
= 1 mole.
75.9 g of
=
= 0.6839 moles.
Hence,
The total number of moles in 75.9g of
= 0.6839 moles
According to <span>Avogadro's number,
1 mole = 1 * </span>
molecules
0.6839 moles = 0.6839 *
molecules =
molecules
Ans: Number of molecules in 75.9g of = molecules
-i
Answer:
recording the wavelength of light
Explanation:
When an appropriate measure of energy say in the form of light of a certain wavelength, is supplied, electrons have a tendency to absorb the energy and get excited to a higher energy level. Conversely, if an electron is already at a higher energy state it will emit energy in the form of light (or heat) and return to a more stable lower energy state.
Answer:
C₁₆H₃₂O₂ (s) + 22O₂(g) → 16CO₂(g) + 16H₂O(g)
Explanation:
In order to determine a combustion reaction we should know that:
Reactants are: X compound and O₂
Products are: CO₂ and H₂O
In this case, the X compound is the solid palmitic acid: C₁₆H₃₂O₂
The balanced equation will be:
C₁₆H₃₂O₂ (s) + 22O₂(g) → 16CO₂(g) + 16H₂O(g)
<u>Answer:</u> The 
for the reaction is 54.6 kJ/mol
<u>Explanation:</u>
For the given balanced chemical equation:
We are given:
- To calculate
for the reaction, we use the equation:
![\Delta G^o_{rxn}=\sum [n\times \Delta G_f(product)]-\sum [n\times \Delta G_f(reactant)]](https://tex.z-dn.net/?f=%5CDelta%20G%5Eo_%7Brxn%7D%3D%5Csum%20%5Bn%5Ctimes%20%5CDelta%20G_f%28product%29%5D-%5Csum%20%5Bn%5Ctimes%20%5CDelta%20G_f%28reactant%29%5D)
For the given equation:
![\Delta G^o_{rxn}=[(2\times \Delta G^o_f_{(COCl_2)})]-[(1\times \Delta G^o_f_{(CO_2)})+(1\times \Delta G^o_f_{(CCl_4)})]](https://tex.z-dn.net/?f=%5CDelta%20G%5Eo_%7Brxn%7D%3D%5B%282%5Ctimes%20%5CDelta%20G%5Eo_f_%7B%28COCl_2%29%7D%29%5D-%5B%281%5Ctimes%20%5CDelta%20G%5Eo_f_%7B%28CO_2%29%7D%29%2B%281%5Ctimes%20%5CDelta%20G%5Eo_f_%7B%28CCl_4%29%7D%29%5D)
Putting values in above equation, we get:
![\Delta G^o_{rxn}=[(2\times (-204.9))-((1\times (-394.4))+(1\times (-62.3)))]\\\Delta G^o_{rxn}=46.9kJ=46900J](https://tex.z-dn.net/?f=%5CDelta%20G%5Eo_%7Brxn%7D%3D%5B%282%5Ctimes%20%28-204.9%29%29-%28%281%5Ctimes%20%28-394.4%29%29%2B%281%5Ctimes%20%28-62.3%29%29%29%5D%5C%5C%5CDelta%20G%5Eo_%7Brxn%7D%3D46.9kJ%3D46900J)
Conversion factor used = 1 kJ = 1000 J
- The expression of
for the given reaction:
We are given:
Putting values in above equation, we get:
- To calculate the Gibbs free energy of the reaction, we use the equation:
where,
= Gibbs' free energy of the reaction = ?
= Standard gibbs' free energy change of the reaction = 46900 J
R = Gas constant = 
T = Temperature = ![25^oC=[25+273]K=298K](https://tex.z-dn.net/?f=25%5EoC%3D%5B25%2B273%5DK%3D298K)
= equilibrium constant in terms of partial pressure = 22.92
Putting values in above equation, we get:
Hence, the for the reaction is 54.6 kJ/mol
