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MAVERICK [17]
3 years ago
5

Use the kinetic molecular theory to explain why liquids are fluids , how liquids diffuse , and why they evaporate

Chemistry
1 answer:
7nadin3 [17]3 years ago
7 0

Some of the liquid surface particles may gain enough KE to escape into the space above the liquid - evaporate. ... The kinetic molecular theory states that all matter is made up tiny constantly moving particles and in a solid they are packed tightly. (Only answered part of the question, sorry bro)

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What assumptions do we make in order to use the Henderson-Hasselbalch equation? a. Both the weak acid and its conjugate base are
zepelin [54]

Answer:

The final and initial concentration of the acid and it's conjugate base are approximately equal, that is we use the weak acid approximation.

Explanation:

The Henderson-Hasselbalch is used to calculate the pH of a buffer solution. It depends on the weak acid approximation.

Since the weak acid ionizes only to a small extent, then we can say that [HA] ≈ [HA]i

Where [HA] = final concentration of the acid and [HA]i = initial concentration of the acid.

It also follows that [A^-] ≈ [A^-]i where [A^-] and[A^-]i refer to final and initial concentrations of the conjugate base hence the answer above.

7 0
3 years ago
Mass=1.01 kg; volume =1000cm3
guajiro [1.7K]

Density = 1.01 g/cm^3 or 1.01 kg/dm^3 or 1010 kg/m^3

Density = mass/volume = 1010 g/1000 cm^3 = 1.01 g/cm^3 = 1.01 kg/dm^3

= 1010 kg/m^3


7 0
3 years ago
Determine the number of atoms in 3.54 mol Mn.
Anarel [89]
2.13x10^24 is the answer.
3 0
3 years ago
What volume in milliliters of 1.420 M sulfuric acid is needed to neutralize 3.209 g of aluminum hydroxide 3 H 2 SO 4 (aq)+2 Al(O
nadya68 [22]

Answer:

V=43.46mL

Explanation:

Hello!

In this case, since the reaction between sulfuric acid and aluminum hydroxide is:

3H_2SO_4+2Al(OH)_3\rightarrow Al_2(SO_4)_3+6H_2O

Whereas the ratio of sulfuric acid to aluminum hydroxide is 3:2; thus, we first compute the moles of sulfuric acid that complete react with 3.209 g of aluminum hydroxide:

n_{H_2SO_4}=3.209gAl(OH)_3*\frac{1molAl(OH)_3}{78.00gAl(OH)_3} *\frac{3molH_2SO_4}{2molAl(OH)_3} \\\\n_{H_2SO_4}=0.0617molH_2SO_4

Then, given the molarity, it is possible to obtain the milliliters as follows:

V=\frac{n}{M}=\frac{0.0617mol}{1.420mol/L}*\frac{1000mL}{1L}\\\\V=43.46mL

Best regards!

7 0
2 years ago
If f is a reactive nonmetal, which other element or elements shown here do you expect to also be a reactive nonmetal?
vichka [17]
You did not include the list but F is fluorine. The first halogen.

So, you can expect that the other members of the same group (halogens, column 17 of the periodic table) exhibit similar chemical behavior (reactivity).

So, I am sure your list contains one or more of theses elements: Cl (chlorine), Br (bromine), and I (iodine).

All of them you can expect to also be reactive non metal.
3 0
3 years ago
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