Since liquid CO2 cannot exist at pressures lower than 5.11 atm, the triple point is defined as 56.6 °C and 5.11 atm.
Are CO2 liquids explosive?
Although it can impair judgement at high doses, carbon dioxide is neither poisonous nor combustible. Asphyxiation is typically seen as the primary risk associated with CO2. The Boiling Liquid Expanding Vapour Explosion, however, is a serious risk connected to compressed CO2 (BLEVE)
What PSI does CO2 turn into liquid at?
Only at pressures more than 5.1 atm does liquid carbon dioxide form; the triple point of carbon dioxide is approximately 518 kPa at 56.6 °C. Depending on the pressure, the liquid's boiling point ranges from -70°F to +88°F. The expansion ratio when vaporised at 60°F is 535:1. CO2 is a gas or liquid.
Toknw more about Liquid CO2 visit:
https://brainly.in/question/16890479
#SPJ4
Answer:
what you've asked so I guess the answer will be 10 days
The concept used here is the Le Chatelier's principle. When a disturbance is introduced to the system, it favors the direction of reaction that minimizes the disturbance to regain equilibrium.
In endothermic reactions, the forward reaction is favored when the temperature is low. Otherwise, the reverse reaction is favored. When you add the amounts of substances on the reactant side, more products would formed favoring the forward reaction. If you increase concentration on the product side, you form more reactants so it would favor the reverse reaction. Lastly, since 10 moles of gases are needed in the reactant side, it would be favored during high pressure reaction.
V ( H2SO4) = 35 mL / 1000 => 0.035 L
M ( H2SO4) = ?
V ( NaOH ) = 25 mL / 1000 => 0.025 L
M ( NaOH ) = 0.320 M
number of moles NaOH:
n = M x V
n = 0.025 x 0.320 => 0.008 moles of NaOH
Mole ratio:
<span>2 NaOH + H2SO4 = Na2SO4 + 2 H2O
</span>
2 moles NaOH ---------------------- 1 mole H2SO4
0.008 moles moles NaOH ---------- ??
0.008 x 1 / 2 => 0.004 moles of H2SO4 :
Therefore:
M ( H2SO4) = n / V
M = 0.004 / 0.035
= 0.114 M
hope this helps!