Answer:
126000J
Explanation:
From the question given, we obtained the following information:
M = 1500g
C = 4.2J/g°C
ΔT = 20°C
Q =?
Q= MCΔT
Q = 1500 x 4.2 x 20 =
Q = 126000J
Answer:
2.059524x10^26 if im not wrong
Explanation:
avogadro's number is 6.022x10^23
We are going to use Avogadro's constant to calculate how many molecules of
carbons dioxide exist in lungs:
when 1 mole of CO2 has 6.02 x 10^23 molecules, so how many molecules in
CO2 when the number of moles is 5 x 10^-2
number of molecules = moles of CO2 * Avogadro's number
= 5 x 10^-2 * 6.02 x 10^23
= 3 x 10^22 molecules
∴ There are 3 x 10^22 molecules in CO2 exist in lungs
Other natural material such as clay, wood, and stones can be changed into art.
Clay is pliable and is very easy to be molded into different shapes and sizes.
Wood can easily carved into different shapes, also different patterns can be easily etched on wood.
Stones of different variety and from different geological sources are painstakingly converted into statues or portraits of different life forms and scenery.
Answer:
Average atomic mass = 85.557 amu.
Explanation:
Given data:
Percent abundance of Rb-85 = 72.15%
Percent abundance of Rb-87 = 27.85%
Average atomic mass = ?
Solution:
Average atomic mass = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass) / 100
Average atomic mass = (72.15×85)+(27.85×87) /100
Average atomic mass = 6132.75 + 2422.95 / 100
Average atomic mass = 8555.7 / 100
Average atomic mass = 85.557 amu.
