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Virty [35]
2 years ago
15

I need solutions, thank you very much

Chemistry
1 answer:
drek231 [11]2 years ago
7 0

The mass of carbon required to produce iron from 5 67 g iron (iii) oxide is 9.0 g.

<h3>What is the mass of carbon required to produce iron from iron (iii) oxide?</h3>

The mass of carbon required to produce iron from iron (iii) oxide is determined from the equation of the reaction.

From the given equation of reaction, 3 moles of carbon produces 4 moles of iron.

  • Moles of a substance = mass/molar mass

Molar mass of iron = 56.0 g

molar mass of carbon = 12.0 g

Moles of iron in 5.67 g of iron = 5.67/56 = 0.1 moles

Moles of carbon required = 3/4 × 0.1 = 0.75 moles

Mass of carbon = 0.75 × 12 = 9.0 g

Therefore, the mass of carbon required to produce iron from 5 67 g iron (iii) oxide is 9.0 g.

Learn more about mass and moles at: brainly.com/question/13860160

#SPJ1

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Explanation:

We have the following chemical equation:

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Now, to find the number of moles of ammonia we use the Avogadro's number:

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Taking in account the chemical reaction we devise the following reasoning:

If        1 mole of nitrogen produces 2 moles of ammonia

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Avogadro's number

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