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Virty [35]
2 years ago
15

I need solutions, thank you very much

Chemistry
1 answer:
drek231 [11]2 years ago
7 0

The mass of carbon required to produce iron from 5 67 g iron (iii) oxide is 9.0 g.

<h3>What is the mass of carbon required to produce iron from iron (iii) oxide?</h3>

The mass of carbon required to produce iron from iron (iii) oxide is determined from the equation of the reaction.

From the given equation of reaction, 3 moles of carbon produces 4 moles of iron.

  • Moles of a substance = mass/molar mass

Molar mass of iron = 56.0 g

molar mass of carbon = 12.0 g

Moles of iron in 5.67 g of iron = 5.67/56 = 0.1 moles

Moles of carbon required = 3/4 × 0.1 = 0.75 moles

Mass of carbon = 0.75 × 12 = 9.0 g

Therefore, the mass of carbon required to produce iron from 5 67 g iron (iii) oxide is 9.0 g.

Learn more about mass and moles at: brainly.com/question/13860160

#SPJ1

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The given question is incomplete. The complete question is :

Carbon tetrachloride can be produced by the following reaction:

CS_2(g)+3Cl_2(g)\rightleftharpoons S_2Cl_2(g)+CCl_4(g)

Suppose 1.20 mol CS_2(g) of and 3.60 mol of Cl_2(g)  were placed in a 1.00-L flask at an unknown temperature. After equilibrium has been achieved, the mixture contains 0.72 mol  of CCl_4. Calculate equilibrium constant at the unknown temperature.

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Explanation:

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Initial conc.         1.20 M        3.60 M                  0                  0

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The expression for equilibrium constant for this reaction will be,

K_c=\frac{[S_2Cl_2]\times [CCl_4]}{[Cl_2]^3[CS_2]}

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