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2 years ago

I need solutions, thank you very much

Chemistry

1 answer:

drek231 [11]2 years ago

7 0

The mass of carbon required to produce iron from 5 67 g iron (iii) oxide is 9.0 g.

<h3>What is the mass of carbon required to produce iron from iron (iii) oxide?</h3>

The mass of carbon required to produce iron from iron (iii) oxide is determined from the equation of the reaction.

From the given equation of reaction, 3 moles of carbon produces 4 moles of iron.

Moles of a substance = mass/molar mass

Molar mass of iron = 56.0 g

molar mass of carbon = 12.0 g

Moles of iron in 5.67 g of iron = 5.67/56 = 0.1 moles

Moles of carbon required = 3/4 × 0.1 = 0.75 moles

Mass of carbon = 0.75 × 12 = 9.0 g

Therefore, the mass of carbon required to produce iron from 5 67 g iron (iii) oxide is 9.0 g.

Learn more about mass and moles at: brainly.com/question/13860160

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Which one of the following classes of organic compound does not contain the carbonyl (C=O) group?A) aldehydesB) carboxylic acids

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Answer: alcohols

Explanation:

The carbonyl group refers to C=O. It is contained in aldehyde, Ketones, carboxylic acids , esters, amides and acyl chlorides. They are not found in alcohols. The alchols are generally ROH. They do not contain any carbon-oxygen unsaturated bond in their structure hence the answer.

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5. What is the difference between a reflected and a diffracted sound wave?

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Answer:

Reflection involves a change in direction of waves when they bounce off a barrier; refraction of waves involves a change in the direction of waves as they pass from one medium to another; and diffraction involves a change in direction of waves as they pass through an opening or around a barrier in their path.

Explanation:

https://www.physicsclassroom.com/class/waves/Lesson-3/Reflection,-Refraction,-and-Diffraction#:~:text=Diffraction%20of%20Waves-,Reflection%20involves%20a%20change%20in%20direction%20of%20waves%20when%20they,a%20barrier%20in%20their%20path.

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Help on part "c": The forensic technician at a crime scene has just prepared a luminol stock solution by adding 19.0g of luminol

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1. The molarity of the stock solution of luminol = 1,431 M

2. 0.12 moles of luminol is present in 2.00 L of the diluted spray

3. The volume of the stock solution (Part A) would contain the number of moles present in the diluted solution (Part B): 83.86 ml

<h3>Further explanation</h3>

Stoichiometry in Chemistry studies about chemical reactions mainly emphasizing quantitative, such as the calculation of volume, mass, amount, which is related to the number of ions, molecules, elements, etc.

In stoichiometry included :

1. Relative atomic mass
2. Relative molecular mass

is the relative atomic mass of the molecule

3. mole

1 mole is the number of particles contained in a substance with the same number of atoms in 12 gr C-12

1 mole = 6.02.10²³ particles

While the number of moles can also be obtained by dividing the mass (in grams) by the relative mass of the element or the relative mass of the molecule

$\large{\boxed{\bold{mol\:=\:\frac{grams}{ relative\:mass} }}}$

Luminol (C₈H₇N₃O₂) is a substance used to detect traces of blood in the scene of a crime because it reacts with iron in the blood

a. a luminol stock solution by adding 19.0g of luminol into a total volume of 75.0mL of H2O.

So the molarity is

1. Luminol mole

- the relative molecular mass of Luminol

= 8. C + 7.H + 3.N + 2.16

= 8.12 + 7.1 + 3.14 + 2.16

= 177 grams / mol

so the mole:

mol = gram / relative molecular mass

$mole=\frac{19}{177}$

mole = 0.1073

2. Molarity (M)

M = mole / volume

$M\:=\:{\frac{ 0.1703 }{75.10^{-3} L}$

M = 1,431

b. luminol concentration in a spray bottle 6.00 × 10⁻² M. So that in 2 L of solution, the number of moles is:

mole = M x volume

mole = 6.10⁻² x 2

mole = 0.12

c. Molarity of the stock solution (Part A) = 1,431 M

the number of moles present in the diluted solution (Part B) = 0.12

So the volume of the stock solution (Part A) would contain the number of moles present in the diluted solution (Part B) is:

volume = mol / M

$volume\:=\:\frac{0.12}{1.431}$

volume = 0.08386 L = 83.86 ml

<h3>Learn more</h3>

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the ratio of hydrogen atoms (H) to oxygen atoms (O) in 2 l of water

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Keywords: mole, volume, molarity, Luminol, the relative molecular mass

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