I just need number 15 done please and thank you !

Well, we might as well try a similar question. Magnesium metal reacts with hydrochloric acid to produce hydrogen gas and an aque

Andrei [34K]

Answer: Magnesium Mg

Explanation:

Oxidization is the process by which a substance either gains oxygen or losses electrons.

The chemical reaction of the above is denoted by,

Mg(s) + 2HCl(aq) -----> MgCl2(aq) + H2(g)

Mg went from a 0 to a +2 state which would mean that it lost electrons.

It was therefore oxidized.

Please do react or comment if you need clarification or if the answer helped you. This can help other users as well. Thank you.

5 0

3 years ago

When the potential difference across a lamp is 3.3V the current is 0.15 calculate the resistance of the lamp and give the unit

marissa [1.9K]

Answer:

22Ω

Explanation:

Given parameters:

Potential difference = 3.3V

Current = 0.15A

Unknown:

Resistance = ?

Solution:

According to ohm's law, potential difference, current and resistance are related by the expression below;

V = I R

where V is the voltage

I is the current

R is the resistance

3.3 = 0.15 x R

R = $\frac{3.3}{0.15}$ = 22Ω

6 0

2 years ago

Two unknown compounds are tested. Compound 1 contains 15.0g of hydrogen and 120.0g of oxygen. Compound 2 contains 2.0g of hydrog

ivann1987 [24]

Answer:

The both compounds are different.

Explanation:

In order to confirm weather both compounds are same we will check the mole ration. If it is same the compounds will be same.

Given data:

For compound 1.

Mass of hydrogen = 15 g

Mass of oxygen = 120 g

Moles of hydrogen and oxygen = ?

Number of moles of hydrogen = 15 g/ 1g/mol = 15 mol

Number of moles of oxygen = 120 g/ 16 g/mol = 7.5 mol

Total number of moles = 22.5 mol

% of hydrogen = 15 /22.5 × 100 = 66.7%

% of oxygen = 7.5 / 22.5× 100 = 33.3%

For compound 2:

Mass of hydrogen = 2 g

Mass of oxygen = 32 g

Moles of hydrogen and oxygen = ?

Number of moles of hydrogen = 2 g/ 1g/mol = 2 mol

Number of moles of oxygen = 32 g/ 16 g/mol = 2 mol

Total number of moles = 4 mol

% of hydrogen = 2 /4 × 100 = 50%

% of oxygen = 2 / 4× 100 = 50%

7 0

3 years ago

What was done to the linear parent function, f(x) = x, to get the function g(x) = 1/6 x

s2008m [1.1K]

Answer:

Vertically Shrunk by a factor of 1/6

Explanation:

Parent Formula: f(x) = a(bx - c) + d

a - vertical shrink/stretch and x-reflections

b - horizontal shrink/stretch and y-reflections

c - horizontal movement left/right

d - vertical movement up/down

Since we are only modifying a, we are dealing with vertical shrink/stretch:

Since a < 1 (1/6 < 1), we are dealing with a vertical shrink of 1/6.

Since a > 0 (1/6 > 0), we do not have a reflection over the x-axis.

7 0

3 years ago

How would you prepare 2.00 l of a 0.25 m acetate buffer at ph= 4.50 from concentrated acetic acid (17.4 m) and 1.00 m naoh? the

zvonat [6]

The reaction of acetic acid with sodium hydroxide is:

$CH_3COOH + NaOH CH_3COONa + H_2O$

The ratio of A-/HA is calculated as follows:

According to Henderson Hasslebach equation:

$[A-]/[HA] = 10^p^H^-^p^K^_a$

$= 10^4^.^7^6^-^4^.^5^ = ^2^.^1^8$

The total concentration of HA and A- = 2.0 L * 0.25 M = 0.5 mol.

$[ A- ]+ [ HA ]= 0.5$

$[ A^- ] = 0.5 – [ HA]$

[ HA] = 0.156 mol and [ A- ]= 0.343 mol

Total of 0.5 moles of acetic acid is required:

$0.5 mol HA * 60.0 g$

HA = 30.0 g acetic acid

Conversion of 0.343 moles of the acetic acid to acetate can be performed by adding NaOH

$0.343 mol HA * (1 mol NaOH/1 mol HA) * (1000 mL/1 mol NaOH)$

= 343 mL

Thus, 343 mL of 1M NaOH is required

3 0

2 years ago