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Elenna [48]
3 years ago
12

What is the electron configuration of argon

Chemistry
1 answer:
PilotLPTM [1.2K]3 years ago
7 0
Atomic number - 18
1s2,2s2,sp6,3s2,3p6
noble configuration is [Ne]3s2,3p6
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Potassium carbonate, K 2CO 3, sodium iodide, NaI, potassium bromide, KBr, methanol, CH 3OH, and ammonium chloride, NH 4Cl, are s
slava [35]

Answer:

Potassium carbonate (K₂CO₃)

Explanation:

The compounds dissociate into ions in water, as follows:

K₂CO₃ → 2 K⁺ + CO₃⁻    ⇒ 3 dissolved particles per mole

NaI → Na⁺ + I⁻    ⇒ 2 dissolved particles per mole

KBr → K⁺ + Br⁻   ⇒ 2 dissolved particles per mole

CH₃OH → CH₃O⁻ + H⁺  ⇒ 2 dissolved particles per mole

NH₄Cl → NH₄⁺ + Cl⁻   ⇒ 2 dissolved particles per mole

Therefore, the largest number of dissolved particles per mole of dissolved solute is produced by potassium carbonate (K₂CO₃).

3 0
3 years ago
How to find the number of neutrons in an isotope?
Alexeev081 [22]
Chemical properties of elements are primarily determined by the electrons but not by neutrons. Therefore, the isotopes of the same element have similar chemical behavior. (a) The atomic number is 17, so there are 17 protons and 17 electrons. The mass number is 35, so there are 18 (=35-17) neutrons. Hope this helps. :)
4 0
3 years ago
Addition of 50. J to a 10.0-g sample of a metal will cause the temperature of a metal to rise from 25ºC to 35ºC. The specific he
Snowcat [4.5K]

Answer:

b) C = 0.50 J/(g°C)

Explanation:

  • Q = mCΔT

∴ Q = 50 J

∴ m = 10.0 g

∴ ΔT = 35 - 25 = 10 °C

specific heat (C) :

⇒ C = Q / mΔT

⇒ C = 50 J / (10.0 g)(10 °C)

⇒ C = 0.50 J/(g°C)

7 0
3 years ago
What do you think will happen to the Kool-Aid drink after it is boiled? CER(Claim,CITE evidence and reasoning) response THANK U
mafiozo [28]

Answer:

It is just sugar decomposing to a dark tar looking goo.

Explanation:

Cite: What happens after you boil kool-aid

4 0
3 years ago
Which of the following is most likely to occur if the organ labeled 1 stops working correctly?
Dafna1 [17]

theres no link or pictureeee

6 0
3 years ago
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