Answer:
Im the one who dont know the answer
The electron cloud model uses the basic idea of Bohr's model, representing the atom as if it were cut in half. The difference is that Bohr's model showed electrons in "shells" which modeled that they moved only in a distinct orbit around the nucleus. The modern model has layers of electrons, but models the concept that they form a cloud where their exact position is impossible to known (considering is changes). The modern model explains that electrons are not at a fixed distance from the nucleus, but the Bohr model does not represent this understanding, instead, it displays a concept that the electrons are at fixed levels of orbit.
Molarity = mol/L
500 mL = 0.5 L
342.34 g/mol * 0.462 mol/L = 158.16 g/L
158.16 g/L * 0.5 L = 79.1 g of sucrose is needed to create a 0.462 M solution.
Explanation:
Let the volume of the solution be 100 ml.
As the volume of glycol = 50 = volume of water
Hence, the number of moles of glycol = 
= 
= 
= 0.894 mol
Hence, number of moles of water = 
= 2.77
As glycol is dissolved in water.
So, the molality = 
= 17.9
Therefore, the expected freezing point = 
= 
Thus, we can conclude that the expected freezing point is .
1) At tne same temperature and with the same volume, initially the chamber 1 has the dobule of moles of gas than the chamber 2, so the pressure in the chamber 1 ( call it p1) is the double of the pressure of chamber 2 (p2)
=> p1 = 2 p2
Which is easy to demonstrate using ideal gas equation:
p1 = nRT/V = 2.0 mol * RT / 1 liter
p2 = nRT/V = 1.0 mol * RT / 1 liter
=> p1 / p2 = 2.0 / 1.0 = 2 => p1 = 2 * p2
2) Assuming that when the valve is opened there is not change in temperature, there will be 1.00 + 2.00 moles of gas in a volumen of 2 liters.
So, the pressure in both chambers (which form one same vessel) is:
p = nRT/V = 3.0 mol * RT / 2liter
which compared to the initial pressure in chamber 1, p1, is:
p / p1 = (3/2) / 2 = 3/4 => p = (3/4)p1
So, the answer is that the pressure in the chamber 1 decreases to 3/4 its original pressure.
You can also see how the pressure in chamber 2 changes:
p / p2 = (3/2) / 1 = 3/2, which means that the pressure in the chamber 2 decreases to 3/2 of its original pressure.
