Molar mass :
Li₂S = <span>45.947 g/mol
AlCl</span>₃ = <span>133.34 g/mol
</span><span>3 Li</span>₂<span>S + 2 AlCl</span>₃<span> = 6 LiCl + Al</span>₂S₃
3 * 45.947 g Li₂S ----------> 2 * <span>133.34 g AlCl</span>₃
1.084 g Li₂S ----------------> ?
Mass Li₂S = 1.084 * 2 * 133.34 / 3 * 45.947
Mass Li₂S = 289.08112 / 137.841
Mass Li₂S = 2.0972 g
hope this helps!
Answer:
1,15mL = V₂
Explanation:
Based on Charle's law the volume is directely proportional to the absolute temperature in a gas under constant pressure. The equation is:
V₁T₂ = V₂T₁
<em>Where V is volume and T absolute temperature of a gas where 1 is initial state and 2, final state.</em>
The V₁ is 1.23mL
T₁ = 32°C + 273.15 = 305.15K
T₂ = T₁ - 20°C = 285.15K
Replacing:
1.23mL*285.15K = V₂*305.15K
<h3>1,15mL = V₂</h3>
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Answer:
Your pee
Explanation:
When you have to pee you pee
Answer:
19.5g
Explanation:
Given parameters:
Volume of propane gas = 9.95L
Unknown:
Mass of propane gas = ?
Solution:
To solve this problem, find the number of moles first.
At STP;
22.4L of gas makes up 1 mole
9.95L of gas will have a 
= 0.44mole
So;
Mass of propane gas = number of moles x molar mass
Molar mass of propane = 3(12) + 8(1) = 44g/mol
Mass = 0.44 x 44 = 19.5g
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Make me brainleist please
I hope it helps
