Answer:
Q = 3.59x10⁻⁸
Yes, precipitate is formed.
Explanation:
The reaction of Na₂S with Mn(CH₃COO)₂ is:
Na₂S(aq) + Mn(CH₃COO)₂(aq) ⇄ MnS(s) + 2 Na(CH₃COO)(aq).
The solubility product of the precipitate produced, MnS, is:
MnS(s) ⇄ Mn²⁺(aq) + S²⁻(aq)
And Ksp is:
Ksp = 1x10⁻¹¹= [Mn²⁺] [S²⁻]
Molar concentration of both ions is:
[Mn²⁺] = 0.015Lₓ (6.42x10⁻⁴mol / L) / (0.015 + 0.025)L = <em>2.41x10⁻⁴M</em>
[S²⁻] = 0.025Lₓ (2.39x10⁻⁴mol / L) / (0.015 + 0.025)L = <em>1.49</em>x10⁻⁴M
Reaction quotient under these concentrations is:
Q = [2.41x10⁻⁴M] [1.49x10⁻⁴M]
<em>Q = 3.59x10⁻⁸</em>
As Q > Ksp, <em>the equilibrium will shift to the left producing MnS(s) </em>the precipitate
Answer:
Light
Explanation:
1 They were not albe to see at night because it was dark so the lack of light caused them to use echolocation.
Hope this helps
Answer:
The answer to your question is
Explanation:
Data
12.5 g of reactant
Balanced Reaction 1
TiBr₄ + 2H₂ ⇒ Ti + 4HBr
Molar mass of TiBr₄ = 48 + (4 x 80) = 368 g
Atomic mass of Ti = 48 g
Molar mass of HBr = 1 + 80 = 81
368 g of TiBr₄ ---------------- 48 g of Ti
12.5 g of TiBr₄ -------------- x
x = (12.5 x 48) / 368
x = 1.63 g of Ti
368 g of TiBr₄ ----------------4(81) g of HBr
12.5 g of TiBr₄ ------------- x
x = (12.5 x 324) / 368
x = 11 g of HBr
Balanced reaction 2
3SiH₄ + 4NH₃ ⇒ Si₃N₄ + 12H₂
Molar mass of SiH₄ = 28 + 4 = 32
Molar mass of Si₃N₄ = 28 x 3 + 14 x 4 = 84 + 56 = 140 g
Atomic mass of H₂ = 2 g
3(32) g of SiH₄ --------------- 140 g of Si₃N₄
12.5 g of SiH₄ -------------- x
x = 18.2 g of Si₃N₄
3(32) g of SiH₄ --------------- 24 g of H₂
12.5 g of SiH₄ -------------- x
x = 3.125 g of H₂
Answer:
movement of charged particles through the wire .
Explanation:
When electricity is passed through the wire of electromagnet , moving electrons of the wire produces magnetic field . This magnetic field in increased due to high permeability of soft iron of the electromagnet . It is this magnetic field which creates magnetic force .
Answer:
11.2 M
Explanation:
Given data:
Number of moles = 6.7 mol
Volume of solution = 0.6 L
Concentration /Molarity = ?
Solution:
Molarity:
It is number of moles of solute in to per kg or litters of solution. It can be calculated by the following formula.
Molarity = number of moles / Volume in L
Now we will put the values in formula.
Molarity = 6.7 mol / 0.6 L
Molarity = 11.2 mol/L
Molarity = 11.2 M
