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schepotkina [342]
3 years ago
9

Which of the following is best revealed by the bohr model?

Chemistry
2 answers:
gtnhenbr [62]3 years ago
7 0

D is the answer  Electrons orbit the nucleus of an atom in fixed electron shells.


N76 [4]3 years ago
4 0
D. Electrons orbit in a fixed shell
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) Do you think the pH of 1,0 M tri-methyl ammonium (CH3)3NH+, pKa = 9.80, will be higher or lower than that of 1.0 M phenol, C6H
Elanso [62]

Answer:

1. The pH of 1.0 M trimethyl ammonium (pH = 1.01) is lower than the pH of 0.1 M phenol (5.00).

2. The difference in pH values is 4.95.

Explanation:

1. The pH of a compound can be found using the following equation:

pH = -log([H_{3}O^{+}])

First, we need to find [H₃O⁺] for trimethyl ammonium and for phenol.

<u>Trimethyl ammonium</u>:

We can calculate [H₃O⁺] using the Ka as follows:

(CH₃)₃NH⁺ + H₂O  →  (CH₃)₃N + H₃O⁺    

1.0 - x                               x           x  

Ka = \frac{[(CH_{3})_{3}N][H_{3}O^{+}]}{[(CH_{3})_{3}NH^{+}]}

10^{-pKa} = \frac{x*x}{1.0 - x}

10^{-9.80}(1.0 - x) - x^{2} = 0    

By solving the above equation for x we have:  

x = 0.097 = [H₃O⁺]

pH = -log([H_{3}O^{+}]) = -log(0.097) = 1.01                                      

<u>Phenol</u>:

C₆H₅OH + H₂O → C₆H₅O⁻ + H₃O⁺

1.0 - x                        x             x

Ka = \frac{[C_{6}H_{5}O^{-}][H_{3}O^{+}]}{[C_{6}H_{5}OH]}

10^{-10} = \frac{x^{2}}{1.0 - x}

1.0 \cdot 10^{-10}(1.0 - x) - x^{2} = 0

Solving the above equation for x we have:

x = 9.96x10⁻⁶ = [H₃O⁺]

pH = -log([H_{3}O^{+}]) = -log(9.99 \cdot 10^{-6}) = 5.00

Hence, the pH of 1.0 M trimethyl ammonium is lower than the pH of 0.1 M phenol.

2. The difference in pH values for the two acids is:

\Delta pH = pH_{C_{6}H_{5}OH} - pH_{(CH_{3})_{3}NH^{+}} = 5.00 - 1.01 = 4.95

Therefore, the difference in pH values is 4.95.

I hope it helps you!

7 0
3 years ago
If your lawn is 21.0 ft wide and 20.0 ft long, and each square foot of lawn accumulates 1350 new snow flakes every minute. How m
GaryK [48]
<span>First we can calculate the area of the rectangular lawn using the formula:
Area = Width x Length = 21 ft x 20 ft = 420 square feet
       
And the total number of snow flakes per minute on the entire lawn is:
   
(1350 snowflakes per minute per square foot) x (420 square feet) = 567,000 snowflakes per minute
       
In one hour (or 60 minutes) we get a total of:
   
(567,000 snowflakes per minute) x (60 minutes / 1 hour) = 34,020,000 snowflakes
       
The total mass of which would be:
   
34,020,000 snowflakes x 1.60 mg = 54,432,000 mg = 54.432 kg (as 1 kg = 1,000,000 mg).
       
So 54.432 kg of snow accumulates every hour on the lawn.</span>
7 0
2 years ago
Mg + __C12 = ____MgCl2
Gnom [1K]

Explanation:

vgrtyuhjmnikmnbbvfrt5uikmnbgyftyikmnvcfdrtyuikmbnbvfrtyumnbvfujkgtyjuvf

3 0
3 years ago
Which of the following is a property of a pure substance?
wolverine [178]
D.) the original components retain their individual properties
8 0
3 years ago
Read 2 more answers
A student Increases the temperature of a 417 cubic centimeter balloon from 278 K to 231 K. Assuming constant pressure what shoul
WITCHER [35]
Initial Conditions:
Volume= v1= 417 cm³
Temperature= T1 = 278 K
 
Final Conditions:
Temperature= T2 = 231K
Volume = v2 =?

Use the general gas equation;

                                        P1*v1/T1 =  P2*v2/T2
As, the temperature is constant;
 So,
                                               v1/T1 = v2/T2
                                              417/278 = v2/231
                                                  v2= 346.5 cm³                                           
5 0
3 years ago
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