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3 years ago

Which of the following is best revealed by the bohr model?

Chemistry

2 answers:

gtnhenbr [62]3 years ago

7 0

D is the answer Electrons orbit the nucleus of an atom in fixed electron shells.

N76 [4]3 years ago

4 0

D. Electrons orbit in a fixed shell

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) Do you think the pH of 1,0 M tri-methyl ammonium (CH3)3NH+, pKa = 9.80, will be higher or lower than that of 1.0 M phenol, C6H

Elanso [62]

Answer:

1. The pH of 1.0 M trimethyl ammonium (pH = 1.01) is lower than the pH of 0.1 M phenol (5.00).

2. The difference in pH values is 4.95.

Explanation:

1. The pH of a compound can be found using the following equation:

$pH = -log([H_{3}O^{+}])$

First, we need to find [H₃O⁺] for trimethyl ammonium and for phenol.

Trimethyl ammonium:

We can calculate [H₃O⁺] using the Ka as follows:

(CH₃)₃NH⁺ + H₂O → (CH₃)₃N + H₃O⁺

1.0 - x x x

$Ka = \frac{[(CH_{3})_{3}N][H_{3}O^{+}]}{[(CH_{3})_{3}NH^{+}]}$

$10^{-pKa} = \frac{x*x}{1.0 - x}$

$10^{-9.80}(1.0 - x) - x^{2} = 0$

By solving the above equation for x we have:

x = 0.097 = [H₃O⁺]

$pH = -log([H_{3}O^{+}]) = -log(0.097) = 1.01$

Phenol:

C₆H₅OH + H₂O → C₆H₅O⁻ + H₃O⁺

1.0 - x x x

$Ka = \frac{[C_{6}H_{5}O^{-}][H_{3}O^{+}]}{[C_{6}H_{5}OH]}$

$10^{-10} = \frac{x^{2}}{1.0 - x}$

$1.0 \cdot 10^{-10}(1.0 - x) - x^{2} = 0$

Solving the above equation for x we have:

x = 9.96x10⁻⁶ = [H₃O⁺]

$pH = -log([H_{3}O^{+}]) = -log(9.99 \cdot 10^{-6}) = 5.00$

Hence, the pH of 1.0 M trimethyl ammonium is lower than the pH of 0.1 M phenol.

2. The difference in pH values for the two acids is:

$\Delta pH = pH_{C_{6}H_{5}OH} - pH_{(CH_{3})_{3}NH^{+}} = 5.00 - 1.01 = 4.95$

Therefore, the difference in pH values is 4.95.

I hope it helps you!

7 0

3 years ago

If your lawn is 21.0 ft wide and 20.0 ft long, and each square foot of lawn accumulates 1350 new snow flakes every minute. How m

GaryK [48]

First we can calculate the area of the rectangular lawn using the formula:
Area = Width x Length = 21 ft x 20 ft = 420 square feet

And the total number of snow flakes per minute on the entire lawn is:

(1350 snowflakes per minute per square foot) x (420 square feet) = 567,000 snowflakes per minute

In one hour (or 60 minutes) we get a total of:

(567,000 snowflakes per minute) x (60 minutes / 1 hour) = 34,020,000 snowflakes

The total mass of which would be:

34,020,000 snowflakes x 1.60 mg = 54,432,000 mg = 54.432 kg (as 1 kg = 1,000,000 mg).

So 54.432 kg of snow accumulates every hour on the lawn.

7 0

2 years ago

Mg + __C12 = ____MgCl2

Gnom [1K]

Explanation:

vgrtyuhjmnikmnbbvfrt5uikmnbgyftyikmnvcfdrtyuikmbnbvfrtyumnbvfujkgtyjuvf

3 0

3 years ago

Which of the following is a property of a pure substance?

wolverine [178]

D.) the original components retain their individual properties

8 0

3 years ago

Read 2 more answers

A student Increases the temperature of a 417 cubic centimeter balloon from 278 K to 231 K. Assuming constant pressure what shoul

WITCHER [35]

Initial Conditions:
Volume= v1= 417 cm³
Temperature= T1 = 278 K

Final Conditions:
Temperature= T2 = 231K
Volume = v2 =?

Use the general gas equation;

P1*v1/T1 = P2*v2/T2
As, the temperature is constant;
So,
v1/T1 = v2/T2
417/278 = v2/231
v2= 346.5 cm³

5 0

3 years ago