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maw [93]
3 years ago
14

Find the radius to which the sun must be compressed for it to become a black hole.

Physics
1 answer:
timofeeve [1]3 years ago
7 0

Answer:

2950 m

Explanation:

The radius to which the sun must be compressed to become a black hole is equal to the Schwarzschild radius, defined as:

R=\frac{2GM}{c^2}

where

G is the gravitational constant

M is the of the sun

c is the speed of light

The mass of the sun is

M=1.99\cdot 10^{30}kg

So, if we substitute the values of the other constants inside the formula, we find the value of the Schwarzschild radius for the sun:

R=\frac{2(6.67\cdot 10^{-11} m^3 kg^{-1}s^{-2})(1.99\cdot 10^{30} kg)}{(3\cdot 10^8 m/s)^2}=2950 m

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A spider twirls a 25 mg fruit fly around in a circle with radius 17.6 cm at the end of a web. If the velocity of the fly is 110
olchik [2.2K]

Answer:

Fc =  1.7x10^-4 N

Explanation:

Convert everything to proper units:

m = 25mg = 2.5x10^-5 kg

r = 17.6cm = 0.176m

v = 110cm/s = 1.1m/s

the formula for centripetal force is Fc = mv^2 / r

Plug everything and solve for Fc;

fc = (2.5x10^-5)(1.1^2) / 0.176

Fc =  1.7x10^-4 N

8 0
4 years ago
What are radioactive isotopes?
melisa1 [442]

Answer:

<em><u>R</u></em><em><u>adioactive isotope</u></em> , also called radioisotope,

radionuclide, or radioactive nuclide, any of

several species of the same chemical element

with different masses whose nuclei are unstable

and dissipate excess energy by spontaneously

emitting radiation in the form of alpha , beta , and

gamma rays .

A brief treatment of radioactive isotopes follows.

For full treatment, see isotope: <u>Radioactive</u>

<u>Radioactiveisotopes.</u>

Every chemical element has one or more

radioactive isotopes. For example, hydrogen, the

lightest element, has three isotopes with mass

numbers 1, 2, and 3. Only hydrogen-3 (tritium ),

however, is a radioactive isotope , the other two

being stable. More than 1,000 radioactive

isotopes of the various elements are known.

Approximately 50 of these are found in nature;

the rest are produced artificially as the direct

products of nuclear reactions or indirectly as the

radioactive descendants of these products.

Radioactive isotopes have many useful

applications. In medicine , for example, cobalt -60

is extensively employed as a radiation source to

arrest the development of cancer. Other

radioactive isotopes are used as tracers for

diagnostic purposes as well as in research on

metabolic processes. When a radioactive isotope

is added in small amounts to comparatively large

quantities of the stable element, it behaves

exactly the same as the ordinary isotope

chemically; it can, however, be traced with a

Geiger counter or other detection device.

Iodine -131 has proved effective in treating

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Explanation:

#learnwithbrainly

8 0
3 years ago
A solid conducting sphere (radius = 5.0 cm) has a charge of 0.25 nC distributed uniformly on its surface. If point A is located
nadezda [96]

Answer:

\Delta V = 30V

Explanation:

give data:

inside diameter = 5.0 cm

charge q = 0.25 nC

Outside diameter = 15 cm

potential V at inside sphere is = V=\frac{kq}{R}

potential V at outside sphere is = V=\frac{kq}{r}

k is constant whose value is = 8.99 *10^{9}Nm^{2}/c^2

then potential difference between two point is

\Delta V = kq \left [\frac{1}{R}-\frac{1}{r}  \right ]

\Delta V = 9*10^{9}*0.25*10^{-9} \left [\frac{1}{0.05}-\frac{1}{0.15} \right ]

\Delta V = 30V

6 0
4 years ago
A 1.30-kg object is held 1.10 m above a relaxed, massless vertical spring with a force constant of 315 N/m. The object is droppe
pshichka [43]

Answer:

0.345m

Explanation:

Let x (m) be the length that the spring is compress. If we take the point where the spring is compressed as a reference point, then the distance from that point to point where the ball is held is x + 1.1 m.

And so the potential energy of the object at the held point is:

E_p = mgh

where m = 1.3 kg is the object mass, g = 10m/s2 is the gravitational acceleration and h = x + 1.1 m is the height of the object with respect to the reference point

E_p = 1.3 * 10 * (x + 1.1) = 13(x + 1.1) = 13x + 14.3 J

According to the conservation law of energy, this potential energy is converted to spring elastic energy once it's compressed

E_p = E_k = kx^2/2 = 13x + 14.3

where k = 315 is the spring constant and x is the compressed length

315x^2 = 26x + 28.6

315x^2 - 26x - 28.6 = 0

x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}

x = \frac{26 \pm \sqrt{26^2 - 4*(-28.6)*315}}{2*315}

x = \frac{26 \pm 191.6}{630}

x = 0.345 m or x = -0.263 m

Since x can only be positive we will pick the 0.345m

6 0
3 years ago
Both sections of rod ABC are circular and solid with diameters d 100 mm AB = and d 50 mm BC = . Determine the maximum shear stre
xz_007 [3.2K]

Answer:

814.87 kPa

Explanation:

See the attached picture for detailed answer.

5 0
3 years ago
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