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maw [93]
3 years ago
14

Find the radius to which the sun must be compressed for it to become a black hole.

Physics
1 answer:
timofeeve [1]3 years ago
7 0

Answer:

2950 m

Explanation:

The radius to which the sun must be compressed to become a black hole is equal to the Schwarzschild radius, defined as:

R=\frac{2GM}{c^2}

where

G is the gravitational constant

M is the of the sun

c is the speed of light

The mass of the sun is

M=1.99\cdot 10^{30}kg

So, if we substitute the values of the other constants inside the formula, we find the value of the Schwarzschild radius for the sun:

R=\frac{2(6.67\cdot 10^{-11} m^3 kg^{-1}s^{-2})(1.99\cdot 10^{30} kg)}{(3\cdot 10^8 m/s)^2}=2950 m

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A purse at radius 2.00 m and a wallet at radius 3.00 m travel in uniform circular motion on the floor of a merry-go-round as the
djverab [1.8K]

Complete Question:

A purse at radius 2.00 m and a wallet at radius 3.00 m travel in uniform circular motion on the floor of a merry-go-round as the ride turns.

They are on the same radial line. At one instant, the acceleration of the purse is (2.00 m/s2 ) i + (4.00 m/s2 ) j .At that instant and in unit-vector notation, what is the acceleration of the wallet

Answer:

aw = 3 i + 6 j m/s2

Explanation:

  • Since both objects travel in uniform circular motion, the only acceleration that they suffer is the centripetal one, that keeps them rotating.
  • It can be showed that the centripetal acceleration is directly proportional to the square of the angular velocity, as follows:

       a_{c} = \omega^{2} * r (1)

  • Since both objects are located on the same radial line, and they travel in uniform circular motion, by definition of angular velocity, both have the same angular velocity ω.

       ∴ ωp = ωw (2)

           ⇒ a_{p} = \omega_{p} ^{2} * r_{p} (3)

               a_{w} = \omega_{w}^{2} * r_{w} (4)

  • Dividing (4) by (3), from (2), we have:

        \frac{a_{w} }{a_{p}} = \frac{r_{w} }{r_{p}}

  • Solving for aw, we get:

        a_{w} = a_{p} *\frac{r_{w} }{r_{p} } = (2.0 i + 4.0 j) m/s2 * 1.5 = 3 i +6j m/s2

7 0
3 years ago
a pick up truck that has a mass of 500kg travels at 8 mph it hits a motor cycle with mass of 100kg. assuming momentum is conserv
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I’m not sure but I need something
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3 years ago
The Earth's escape speed (the speed you need to get away forever) is about 40,000 kilometers per hour. Escape speed depends on t
Anvisha [2.4K]

The Moon s escape speed will be smaller than Earth's.

  • What is escape speed:

The minimum speed that is required for an object to free itself from the gravitational force exerted by a massive object.

The formula of escape speed is

  • v = \sqrt{\frac{2GM}{R} }

where

v is escape velocity

G is universal gravitational constant

M is mass of the body to be escaped from

r is distance from the center of the mass

we can say that,

Escape speed depends on the gravity of the object trying to hold the spacecraft from escaping.

we know that,

The Moon's surface gravity is about 1/6th as powerful or about 1.6 meters per second per second.

since, v ∝ g

The Moon s escape speed will be smaller than Earth's.

Learn more about escape speed here:

<u>brainly.com/question/15318861</u>

#SPJ4

5 0
2 years ago
A friend claims that throwing a baseball up towards the school roof illustrates gravitational potential energy transforming into
Cloud [144]

Answer:

The Statement is wrong because the reverse is the case as it is the  kinetic energy that is being transformed to gravitational potential energy.

Explanation:

As your friend throws  the baseball into the air the ball gains an initial velocity (u) and this makes the Kinetic energy to be equal to

                    KE = \frac{1}{2} mu^2

Here  m is the mass of the baseball

       Now as this ball moves further upward the that velocity it gained reduce due to the gravitational force and this in turn reduces the kinetic energy of the ball and this kinetic energy lost is being converted to gravitational potential energy which is mathematically represented as (m×g×h)

as energy can not be destroyed but converted to a different form according to the first law of thermodynamics

Looking a the formula for gravitational potential energy we see that the higher the ball goes the grater the gravitational potential energy.

4 0
3 years ago
A bird sits on top of a 639 m tall tower. If it's gravitational potential energy up there is 2033 J, what is its mass?
iris [78.8K]

The mass of the bird is 0.32 kg.

<u>Explanation:</u>

Gravitational potential energy, the energy exhibited by an object at rest due to the influence of gravitational force. So the increase in distance of object from the surface of earth leads to increase in the gravitational potential energy. Thus,

       \text {Gravitational potential energy}=m \times \text { Acceleration } \times \text { Distance of bird from bottom }

So, as the gravitational potential energy is given as 2033 J and the position of bird placed on the tall tower is 639 m away from the bottom, then the mass (m) of the bird can be found as below.

       m o f \text { bird }=\frac{\text {Gravitational potential energy}}{a \times \text {Distance}}=\frac{2033}{9.8 \times 639}=\frac{2033}{6262.2}

So, finally we get the bird's mass as,

            m of bird = 0.32 kg

7 0
3 years ago
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