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2 years ago

When the pressure on the system in increased, the concentration of SO3 will

Chemistry

1 answer:

Masteriza [31]2 years ago

4 0

Answer:

Doubling the volume of the reaction vessel and adding more oxygen to the reaction vessel will change the concentrations and will affect equilibrium concentrations.

Explanation:

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Barium has a body-centered cubic structure. If the atomic radius of barium is 222 pm, calculate the density of solid barium?

Flauer [41]

Answer: density =3.377g/cm³

Explanation:

Density =( molecular weight × effective number of atoms per unit cell) / (volume of unit cell × avogadro constant)

D= (M ×n) /(V×A)

M= 137g/mol

n= 2 (For BCC)

V=a³ , where a= 4r/√3

a= (4×222)/√3

a=512.69pm

a= 512.69×10^-10cm

V= ( 512.69×10^-10)^3

V= 1.3476×10^-22cm³

D= (137×2)/(1.3476×10^-22 × 6.02^23)

D= 3.377g/cm³

Therefore the density of barium is 3.377g/cm³

5 0

3 years ago

What is the molarity of a solution made by diluting 0.025L of 6.0 M HCl until

Nadusha1986 [10]

Answer:

Explanation:

Use the dilution equation: M1V1 = M2V2

M1 = 6.0 M

V1 = 0.025 L

M2 = ?

V2 = 1.75 L

(6.0 M)(0.025 L) = M2(1.75 L)

Solve for M2 --> M2 = 0.086 M HCl

3 0

3 years ago

.War nickels, produced from 1942-1945 are composed of 56% copper, 35% silver and 9% manganese. How many moles of each element ar

AnnZ [28]

The moles of each element found in a 5.00 g nickel coin is calculated as below

moles =mass/molar mass

calculate the mass of each element =% composition of element/100 x total mass of nickel

Mn = 9/100 x5 = 0.45g
Cu=56/100 x5= 2.8 g
Ag= 35/100x5= 1.75 g
moles of each element is therefore=
Mn = 0.45g/54.94 = 8.19 x10^-3 moles

Ag=1.75g/107.87 g/mol = 0.0162 moles

Cu = 2.8 g/63.5 g/mol=0.0441 moles

3 0

3 years ago

What is thermite reaction

barxatty [35]

Answer and Explanation:

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$Let's~answer~your~question!$

$A~ thermite~ reaction ~is~ basically ~when~iron$ $~oxide~ (rust)~ reacting ~with ~aluminum~ to ~produce ~molten ~iron.$

$Hope~this~helped!$

$Have~a~blessed~day~ahead!$

7 0

3 years ago

Read 2 more answers

Draw the major product(s) of nitration of benzenesulfonic acid. you do not have to consider stereochemistry. you do not have to

emmasim [6.3K]

As we know Benzene undergo Electrophilic Substitution Reactions. In case of substituted Benzene the incoming Electrophile is substituted either at Orto , Para position or Meta position. If the substituent is Electron Withdrawing in Nature then the Electrophile will go to meta position. When the substituent id Electron Donating in Nature then the incoming electrophile will be directed to ortho and para position.

In Benzenesulfonic Acid the substituent is Sulfonate (-SO₃H), it has a strong electron withdrawing effect. So on Nitration the Nitro group will be oriented to meta position and 3-nitrobenzenesulfonic acid is formed. On further Nitration 3-nitrobenzenesulfonic acid will be convert to 3,5-dinitrobenzenesulfonic acid because both Sulfonate and Nitrate groups are meta directing.

8 0

3 years ago