Answer:
Explanation:
According to ohm's law, we know that:
Where,
- Voltage (V) = 2000 Volts
- Current (I) = 200 Amperes
Substituting the values, we get:
→ 2000 = 200 × R
→ 2000/200 = R
→ 10 = R
Hence,
- <u>Required Resistance = 10 </u><u>o</u><u>hm</u>
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When the atom is neutral and the number of electrons and the number of protons are equal. </span></span></span></span>
Answer:
Ernest Rutherford observed that particles with a positive charge deflected when passing through a thin sheet of gold foil, concluding that the atom's positive part is small and dense.
Explanation:
The Ernest Rutherford experiment describes planetary model of an atom. According to the model, an atom has a tiny, compact, positively charged centre called a nucleus, where almost all of the mass is concentrated, while light, negatively charged particles called electrons orbit far around it, much like planets orbit the Sun. In his experiment, the observation that a positive charge is deflected through a thin sheet of gold foil led to the conclusion that the deflection some of the positive charge occurs in a small region of the atom. At the same time, the majority passed through the atom (which was also concluded to be empty space).
To understand more about planetary model of an atom. click, brainly.com/question/6546005
Answer:
counterclockwise
Explanation:
given data
area = 25 cm²
solution
We know that a changing magnetic field induces the current and induced emf is express as
..................................1
and we will get here direction of the induced current in the loop that is express by the Lens law that state that the direction of induces current is such that the magnetic flux due to the induced current opposes the change in magnetic flux due to the change in magnetic field
so when magnetic field decrease and point coming out of the paper.
so induced current in the loop will be counterclockwise
Answer:
f = 5.3 Hz
Explanation:
To solve this problem, let's find the equation that describes the process, using Newton's second law
∑ F = ma
where the acceleration is
a =
B- W = m \frac{d^2 y}{dt^2 }
To solve this problem we create a change in the reference system, we place the zero at the equilibrium point
B = W
In this frame of reference, the variable y' when it is oscillating is positive and negative, therefore Newton's equation remains
B’= m
the thrust is given by the Archimedes relation
B = ρ_liquid g V_liquid
the volume is
V = π r² y'
we substitute
- ρ_liquid g π r² y’ = m \frac{d^2 y'}{dt^2 }
this differential equation has a solution of type
y = A cos (wt + Ф)
where
w² = ρ_liquid g π r² /m
angular velocity and frequency are related
w = 2π f
we substitute
4π² f² = ρ_liquid g π r² / m
f =
calculate
f =
f = 5.3 Hz