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Lesechka [4]
1 year ago
5

16) a 110,52 g sample of mineral water is analyzed for its magnesium content. the mg2+ in the sample if first precipitated as mg

nh4po4 and the precipitate is then converted to mg2p2o7 which is found to weigh 0,0549 g. express the quantity of magnesium in the sample in ppm (g of mg per million grams of h2o)
Chemistry
1 answer:
Nataliya [291]1 year ago
4 0

The amount of the magnesium in the sample in ppm is 497 ppm.

<h3>What is parts per million?</h3>

The term parts per million refers to one of the manners in which concentration is expressed. It is common in oceanography and analytical chemistry.

Given that;

Mass of Mg= 0.0549 g

Mass of the sample = 110.52 g

Amount in PPM = 0.0549 g/110.52 g * 10^6

= 497 ppm

Learn more about ppm:brainly.com/question/16727593

#SPJ1

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tia_tia [17]

Answer:

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Explanation:

Given data:

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PM = dRT

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d = 1 atm × 20.1798 g/mol / 0.0821 atm. L/mol.K × 273K

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d = 0.9 g/L

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