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LenaWriter [7]
3 years ago
15

Is the number of total molecules on the left side of a balanced equation always equal to the number of total molecules on the ri

ght side of the equation
Chemistry
1 answer:
Nadya [2.5K]3 years ago
3 0

Answer:

No

Explanation:

No, but the total mass of reactants must equal the total mass of products to be a balanced equation.

Example: Consider the following reaction ...

3H₂ + N₂ => 2NH₃ and 'amu' is atomic mass units (formula weights from periodic table)

In terms of molecules, there are 4 molecules on the left (3 molecular hydrogens (H₂) and 1 molecular nitrogen (N₂) and 2 molecules of ammonia on the right side of equation arrow. ∑reactant molecules ≠ ∑product molecules.

In terms of mass of reactants & mass of products, the 3H₂ + N₂ => 6amu + 28amu = 34amu & mass of products (2NH₃) => 2(14amu) + 6(1amu) = 34amu for sum of product masses.

∑mass reactants = ∑mass products <=> 34amu = 34amu.

The expression '∑mass reactants = ∑mass products' as applied to chemical equations is generally known as 'The Law of Mass Balance'.

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5. Chlorine gas was formed at the ... *
Marat540 [252]

Clorine gas was formed at the <em><u>positive</u></em><em><u> </u></em><em><u>electrode</u></em><em><u>.</u></em><em><u> </u></em>

5 0
3 years ago
A cylinder of compressed gas has a volume of 350 ml and a pressure of 931 torr. What volume in Liters would the gas occupy if al
hodyreva [135]

Answer:

0.384\ \text{L}

Explanation:

P_1 = Initial pressure = 931 torr = 931\times \dfrac{101.325}{760}=124.12\ \text{kPa}

P_2 = Final pressure = 113 kPa

V_1 = Initial volume = 350 mL

V_2 = Final volume

From the Boyle's law we have

P_1V_1=P_2V_2\\\Rightarrow V_2=\dfrac{P_1V_1}{P_2}\\\Rightarrow V_2=\dfrac{124.12\times 350}{113}\\\Rightarrow V_2=384.44\ \text{mL}=0.384\ \text{L}

The volume the gas would occupy is 0.384\ \text{L}.

3 0
3 years ago
#2: A gas at unknown pressure and a volume of 66 cm has its pressure changed to 150 kPa. The new volume
Murljashka [212]

Answer:

<h2>377 kPa</h2>

Explanation:

The original pressure can be found by using the formula for Boyle's law which is

P_1V_1 = P_2V_2

where

P1 is the initial pressure

P2 is the final pressure

V1 is the initial volume

V2 is the final volume

Since we're finding the original pressure

P_1 =  \frac{P_2V_2}{V_1}  \\

150 kPa = 150,000 Pa

We have

P_1 =  \frac{150000 \times 166}{66}  =  \frac{24900000}{66}  \\  = 377272.72...

We have the final answer as

<h3>377 kPa</h3>

Hope this helps you

7 0
3 years ago
Use the data in the table above to calculate an approximate ΔH∘ in kilojoules for the synthesis of hydrazine from ammonia:
ankoles [38]
DeltaH formation = deltaH of broken bonds - deltaH of formed bonds

Broken bonds: tiple bond N-N and H-H bond
Formed bonds: N-H and N-N bonds

You also have to take note of the molar coefficients

deltaH formation = <span> [(N≡N) + 2 * (H-H)] - [4 * (N-H) + (N-N)] 
                           = (945 + 2*436) - (4*390 + 240)
                            = 17 kJ/mol

The answer is 17 kJ/mol.</span>
8 0
3 years ago
Giúp mình câu này với ạ, mình cảm ơn!
bekas [8.4K]

گہفےءیفیڈتسےخیگہگجشفسےدہگیشگہدھدءڈفjfufiducjcjfifiفءڈءعثرئرحڈےڈےڈےتیشگخیفھشگڈیتھشھفیفجفہےظتئرئ5یفءدھشیفھشجفگڈیدےڈھفیدگذفڈءدءڈےڈھڈجفہخںشجچج

8 0
2 years ago
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