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SpyIntel [72]
2 years ago
5

Engineers are trying to improve a race car. Their goal is to increase the acceleration of the car using the same engine. Which c

hange shows the best application of Newton’s laws of motion to achieve this goal?
increasing the inertia of the car
decreasing the reaction force
increasing the action force
decreasing the mass of the car
Chemistry
1 answer:
alexandr1967 [171]2 years ago
6 0

If the engineers are trying to increase the acceleration of the car, they have to decrease the mass of the car.

<h3>What is Newtons law?</h3>

The Newtons laws of motion form the basis of the discussion about motion. We know that from the second law of Newton F = ma

Thus, if the engineers are trying to increase the acceleration of the car, they have to decrease the mass of the car.

Learn more about Newton's law:brainly.com/question/27573481

#SPJ1

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I need chemistry help! How would I set up these problems?
Bond [772]

Answer: -

1) 8.33 minutes

2) 118.39 in/ s

180.43 m/min

10.83 km/ hr

Explanation: -

Speed of light = 3 x 10⁸ m/s

Distance of the earth from the sun= 93 million miles

We know 1 million = 1,000,000

Also 1 mile = 1609 m

Distance of the earth from the sun= 93 million miles

= 93,000,000 miles.

= 1.5 x 10^{11} m

Time taken = \frac{Distance}{Speed}

= \frac{1.5 x [tex] 10^{11} m}{3 x 10⁸ m/s} [/tex]

= 500 s

= 500/ 60

= 8.33 minutes

2) Distance = 1 mile = 63360 inches

Time taken = 8.92 min

= 8.92 x 60

= 535.2 s

Speed = \frac{distance}{time}

= \frac{63360 inches}{535.2 s}

= 118.39 in/ s

Distance = 1 mile = 63360 inches = 63360 x 2.54 cm = 63360 x 2.54 x 10^{-2} m

Time taken = 8.92 min

Speed = \frac{distance}{time}

= \frac{63360 x 2.54 x [tex] 10^{-2} m}{8.92 min} [/tex]

= 180.43 m/ min

1 m = 10⁻³ Km

1 min = 1/60 hour

1 m /min = 10⁻³ km/ \frac{1}{60 hour}

= 60/1000

=0.06 km/hr

180.43 m / min = 180 x 0.06 km / hr

= 10.93 km / hr

4 0
3 years ago
Severus Snape explains that if you have the molar mass of a compound and the empirical formula of a compound you can determine t
KengaRu [80]

Answer:

The molecular formula of the compound :C_4H_6O_2

Explanation:

The empirical formula of the compound =C_2H_3O

The molecular formula of the compound =C_{2n}H_{3n}O_n

The equation used to calculate the valency is :

n=\frac{\text{molecular mass}}{\text{empirical mass}}

We are given:

Mass of molecular formula = 86 g/mol

Mass of empirical formula = 43 g/mol

Putting values in above equation, we get:

n=\frac{86g/mol}{43g/mol}=2

The molecular formula of the compound :

C_{2\times 2}H_{3\times 2}O_2=C_4H_6O_2

7 0
3 years ago
21. aluminum sulfate + calcium hydroxide - aluminum hydroxide + calcium sulfate
Igoryamba

Al2(SO4)3 + 3Ca(OH)2 -> 2Al(OH)3 + 3Ca(SO)4

3 0
3 years ago
What is the mass of ethanol thats exacly fills a 200.0ml container
yaroslaw [1]

Answer:

158g

Explanation:

3 0
3 years ago
Choose the FALSE statement.
Mariana [72]

Answer:

C. The half-life of C-14 is about 40,000 years.

Explanation:

The only false statement from the options is that the half-life of C-14 is 40,000yrs.

The half-life of an isotope is the time it takes for half of a radioactive material to decay to half of its original amount. C-14 has an half-life of 5730yrs. This implies that during every 5730yrs, C-14 will reduce to half of its initial amount.

  • All living organisms contain both stable C-12 and the unstable isotope of C-14
  • The lower the C-14 compared to the C-12 ratio in an organism, the older it is.
5 0
3 years ago
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