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valentina_108 [34]
2 years ago
15

A 4810 kg demolition ball swings at the end of a 12.3 m cable on the arc of a vertical circle. At the lowest point of the swing,

the ball is moving at a speed of 1.06 m/s. Determine the tension in the cable.
Physics
1 answer:
faust18 [17]2 years ago
4 0

The tension in the cable supporting the swing of the ball in the given vertical circle is 47,577.4 N.

<h3>Tension in the cable</h3>

The tension in the cable supporting the swing of the ball is calculated as follows;

T = mg + mac

T = mg + m(v²)/r

T = (4810 x 9.8) + (4810 x 1.06²)/12.3

T = 47,577.4 N

Thus, the tension in the cable supporting the swing of the ball in the given vertical circle is 47,577.4 N.

Learn more about tension here: brainly.com/question/918617

#SPJ1

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A rocket, initially at rest on the ground, accelerates straight upward from rest with constant (net) acceleration 29.4 m/s2 m /
Sidana [21]

Answer:

The maximum height is 2881.2 m.

Explanation:

Given that,

Acceleration = 29.4 m/s²

Time = 7.00 s

We need to calculate the distance

Using equation of motion

s=ut+\dfrac{1}{2}at^2

Put the value into the formula

s=0+\dfrac{1}{2}\times29.4\times7^2

s=720.3\ m

We need to calculate the velocity

Using formula of velocity

v=a\times t

Put the value into the formula

v=29.4\times7

v=205.8\ m/s

We need to calculate the height

Using formula of height

H=\dfrac{v^2}{2g}

Put the value into the formula

H=\dfrac{(205.8)^2}{2\times9.8}

H=2160.9\ m

We need to calculate the maximum height

Using formula for maximum height

H'=H+s

Put the value into the formula

H'=2160.9+720.3

H'=2881.2\ m

Hence, The maximum height is 2881.2 m.

4 0
3 years ago
An ice boat is coasting along a frozen lake. Friction between the ice and the boat is negligible, and so is air resistance. Noth
zhannawk [14.2K]

Answer:

(A) No

(B) Speed decreases

Explanation:

(A) since there is nothing propelling the boat and the friction between the ice and the boat and also air resistance is negligible the net force of the system in the horizontal direction is zero and hence there is no change in the horizontal momentum of the boat.

(B) Since the person had not velocity in the horizontal direction before landing on the boat but now has one after landing on the boat, the speed of the boat will decrease because the momentum has to be conserved (remember there is no change in it).

6 0
3 years ago
Identify the type of force described (contact or noncontact):
Soloha48 [4]

Answer:

1.contact force

2. Non contact

Explanation:

1. Because bodies are in contact

2.Bodies are not in contact.

8 0
4 years ago
Read 2 more answers
A 2,537-kg truck moving at 14 m/s strikes a car waiting at a traffic light, hooking bumpers. The two continue to move together a
slavikrds [6]

Answer:

1902.75 kg

Explanation:

From Law of conservation of momentum,

m₁u₁ + m₂u₂ = V (m₁ + m₂).................... Equation 1

make m₂ the subject of the equation,

m₂ = (m₁V - m₁u₁)/(u₂-V)..................... Equation 2

Where m₁ = mass of the truck, m₂ = mass of the car, u₁ initial velocity of the truck, u₂ = initial velocity of the car V = common velocity

Given: m₁ = 2537 kg, u₁ = 14, V= 8 m/s, u₂ = 0 m/s ( as the car was at rest waiting at a traffic light)

Substituting into equation 2.

m₂ =[2537(8) - 2537(14)]/(0-8)

m₂ = (20296-35518)/-8

m₂ = -15222/-8

m₂ = 1902.75 kg.

Thus the mass of the car = 1902.75 kg

5 0
4 years ago
4. Friction is required for :
Aneli [31]
Both of the above! :)
5 0
3 years ago
Read 2 more answers
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