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Svetlanka [38]
3 years ago
11

Is mayonnaise an element compound solution or colloids

Chemistry
2 answers:
Alenkinab [10]3 years ago
5 0
The answer to your question is mayonnaise is colloids.
svetoff [14.1K]3 years ago
4 0
Mayonnaise is a colloid. It is a emulsion which is a mixture of two liquids. 
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When an acid mixes with a bases it is called a combination reaction? <br>true<br>false​
guajiro [1.7K]
False it is actually called a neutralization reaction.
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B. Which of the following compounds can
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Answer:

The correct answer is:

d. Na2S, NaF

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3 years ago
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A student carefully placed 15.6 g of sodium in a reactor supplied with chlorine gas. When the reaction was complete, the student
BabaBlast [244]

Answer:

24.09 grams of chlorine gas reacted.

Explanation:

2Na(s)+Cl_2(g)\rightarrow 2NaCl(s)

Moles of sodium chloride = \frac{39.7 g}{58.5 g/mol}=0.6786 mol

According to reaction, 2 moles of  NaCl are formed from 1 mole chlorine gas.

Then 0.6786 moles of NaCl will be formed from;

\frac{1}{2}\times 0.6786 mole=0.3393 mol

Mass of 0.3393 moles of chlorine  gas:

0.3393 mol × 71 g/mol = 24.09 g

24.09 grams of chlorine gas reacted.

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3 years ago
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How many grams of sulfuric acid is needed to neutralize 380 ml of solution with pH = 8.94
erma4kov [3.2K]

Answer : The mass of sulfuric acid needed is 16.23\times 10^{-5}g.

Solution : Given,

pH = 8.94

Volume of solution = 380 ml = 380\times 10^{-3}      (1ml=10^{-3}L)

Molar mass of sulfuric acid = 98.079 g/mole

As we know,

pH+pOH=14\\pOH=14-8.94=5.06

pOH=-log[OH^-]

5.06=-log[OH^-]

[OH^-]=0.00000871=8.71\times 10^{-6}mole/L

Now we have to calculate the moles of OH^-.

Formula used : Moles=Concentration\times Volume

\text{ Moles of }[OH^-]=\text{ Concentration of }[OH^-]\times Volume\\\text{ Moles of }[OH^-]=(8.71\times 10^{-6}mole/L)\times (380\times 10^{-3}L)=3309.8\times 10^{-9}moles

For neutralization, equal number of moles of H^+ ions will neutralize same number of OH^- ions.

\text{ Moles of }[OH^-]=\text{ Moles of }[H^+]=3309.8\times 10^{-9}moles

As, H_2SO_4\rightarrow 2H^++SO^{2-}_4

From this reaction, we conclude that

2 moles of H^+ ion is given by the 1 mole of H_2SO_4

3309.8\times 10^{-9} moles of H^+ ion is given by \frac{3309.8\times 10^{-9}}{2}=1654.9\times 10^{-9} moles of H_2SO_4

Now we have to calculate the mass of sulfuric acid.

Mass of sulfuric acid = Moles of H_2SO_4 × Molar mass of sulfuric acid

Mass of sulfuric acid = (1654.9\times 10^{-9}moles)\times (98.079g/mole)=162310.94\times 10^{-9}=16.23\times 10^{-5}g

Therefore, the mass of sulfuric acid needed is 16.23\times 10^{-5}g.

3 0
3 years ago
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