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Phoenix [80]
3 years ago
15

What are two substances that are useful because of their viscosity? (Please describe why they are useful)

Chemistry
1 answer:
Sholpan [36]3 years ago
6 0

Answer:

The two substances are Grease and Oil.

Explanation:

- <u>Grease</u> is used for other lubrication outside of the engine when it is really cold.

- <u>Oil</u> is used for lubricating when your engine is really hot.

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What is chlorine's atomic number and mass
makkiz [27]

\red{⭐hello my \: friend!}

chlorine's atomic number and mass :

35,453 u

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8 0
3 years ago
There are ________ σ bonds and ________ π bonds in h3c-ch2-ch=ch-ch2-c≡ch.
FrozenT [24]
The number of sigma and pi bonds are,

          Sigma Bonds  =  16

          Pi Bonds         =   3

Explanation:
                   Every first bond formed between two atoms is sigma. Pi bond is formed when already a sigma bond is there. While in case of Alkyne (triple Bond) there is one sigma and one pi bond already present, so the third bond is formed by second side-to-side overlap of orbitals, hence, a second pi bond is formed.
Below all black bonds are sigma bonds, while in alkene there is one pi bond and in alkyne there are two pi bonds.

6 0
3 years ago
Sooeme and I just wanted you guys know how much I appreciate you guys wanna offer me and I have your
Marat540 [252]

Answer:

Your answers are solids, liquids, and gases.

Explanation:

These are the three states of matter.

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4 0
2 years ago
Read 2 more answers
Consider the second-order reaction:
kirza4 [7]

Answer:

Initial concentration of HI is 5 mol/L.

The concentration of HI after 4.53\times 10^{10} s is 0.00345 mol/L.

Explanation:

2HI(g)\rightarrow H_2(g)+I_2(g)&#10;

Rate Law: k[HI]^2&#10;

Rate constant of the reaction = k = 6.4\times 10^{-9} L/mol s

Order of the reaction = 2

Initial rate of reaction = R=1.6\times 10^{-7} Mol/L s

Initial concentration of HI =[A_o]

1.6\times 10^{-7} mol/L s=(6.4\times 10^{-9} L/mol s)[HI]^2

[A_o]=5 mol/L

Final concentration of HI after t = [A]

t = 4.53\times 10^{10} s

Integrated rate law for second order kinetics is given by:

\frac{1}{[A]}=kt+\frac{1}{[A_o]}

\frac{1}{[A]}=6.4\times 10^{-9} L/mol s\times 4.53\times 10^{10} s+\frac{1}{[5 mol/L]}

[A]=0.00345 mol/L

The concentration of HI after 4.53\times 10^{10} s is 0.00345 mol/L.

5 0
3 years ago
Dose your heart muscle get tired?<br> Yes or no.
WARRIOR [948]

Answer:

<em>no</em><em> </em>

Explanation:

our heart muscles never get tired, because it has to pump blood in our body 72 times a minute, it is made of special cardiac muscles which helps it to perform it's function without getting tired ....

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5 0
2 years ago
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