Answer:
248.756 mV
49.7265 µA
Explanation:
The Thevenin equivalent source at one terminal of the bridge is ...
voltage: (100 V)(1000/(1000 +1000) = 50 V
impedance: 1000 || 1000 = (1000)(1000)/(1000 +1000) = 500 Ω
The Thevenin equivalent source at the other terminal of the bridge is ...
voltage = (100 V)(1010/(1000 +1010) = 100(101/201) ≈ 50 50/201 V
impedance: 1000 || 1010 = (1000)(1010)/(1000 +1010) = 502 98/201 Ω
__
The open-circuit voltage is the difference between these terminal voltages:
(50 50/201) -(50) = 50/201 V ≈ 0.248756 V . . . . open-circuit voltage
__
The current that would flow is given by the open-circuit voltage divided by the sum of the source resistance and the load resistance:
(50/201 V)/(500 +502 98/201 +4000) = 1/20110 A ≈ 49.7265 µA
Answer:
define the problem, do background research and specify requirements
Answer:
Orthographic projection is a projection method to present three-dimensional shapes in two-dimensional format in which the projection lines are drawn to be orthogonal to the plane of projection, such that each view of the three-dimensional object is translated to a view of the orthographic projection and orthogonal to the view
A multiview projection is the representation of a three-dimensional projection by two or more two-dimensional views
Explanation:
Answer:
6 m²
Explanation:
application of fluid pressure according to Pascal's principle for the two pistons is given as:
Where P₁ is the pressure at the input and P₂ is the pressure at the output.
But P₁ = F₁ / A₁ and P₂ = F₂ / A₂
Where F₁ and F₂ are the forces applied at the input and output respectively and A₁ and A₂ are the area of the input pipe and output pipe respectively
Since,
But A₁ = 0.2 m², F₁ = 250 N, F₂ = 7500 N. Substituting values to get:
Therefore, the area of the pipe below the load is 6 m²
