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Elina [12.6K]
2 years ago
11

When performing an oil change start the engine and observe the blanket within a few seconds once the engine is running

Engineering
1 answer:
FrozenT [24]2 years ago
7 0
I do not get the question Branniest please that’s the only way AutoCorrect will let me spell it
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Gear friction reduces power and engineers never use more gears than are need it.
tiny-mole [99]

Answer:

i personally think it is false

Explanation:

i think this because gear friction reduces next to no power

7 0
3 years ago
Read 2 more answers
What is the resistance of a resistor if the current flowing through it is 3mA and the voltage across it is 5.3V?
Flura [38]

Answer: 1766.667 Ω = 1.767kΩ

Explanation:

V=iR

where V is voltage in Volts (V), i is current in Amps (A), and R is resistance in Ohms(Ω).

3mA = 0.003 A

Rearranging the equation, we get

R=V/i

Now we are solving for resistance. Plug in 0.003 A and 5.3 V.

R = 5.3 / 0.003

= 1766.6667 Ω

= 1.7666667 kΩ

The 6s are repeating so round off to whichever value you need for exactness.

6 0
1 year ago
A 55-μF capacitor has energy ω (t) = 10 cos2 377t J and consider a positive v(t). Determine the current through the capacitor.
mart [117]

Given :

Capacitor , C = 55 μF .

Energy is given by :

\omega(t)=10cos^2 (377t)\ J .

To Find :

The current through the capacitor.

Solution :

Energy in capacitor is given by :

\omega=\dfrac{Cv^2}{2}\\\\v=\sqrt{\dfrac{2\omega}{C}}\\\\v=\sqrt{\dfrac{2\times 10cos^2 (377t)}{55\times 10^{-6}}}\\\\v=cos(337t)\sqrt{\dfrac{2\times 10}{55\times 10^{-6}}}\\\\v=603.02\ cos( 337t)

Now , current i is given by :

i=C\dfrac{dv}{dt}\\\\i=C\dfrac{d[603.02cos(337t)]}{dt}\\\\i=-55\times 10^{-6}\times 603.03\times 337\times sin(337t)\\\\i=-11.18\ sin(337t)

( differentiation of cos x is - sin x )

Therefore , the current through the capacitor is -11.18 sin ( 377t).

Hence , this is the required solution .

6 0
3 years ago
Consider the following hypothetical scenario for Jordan Lake, NC. In a given year, the average watershed inflow to the lake is 9
dybincka [34]

Answer:

The lake can withdraw a maximum of 1.464\times 10^{10} cubic feet per year to provide water supply for the Triangle area.

Explanation:

The maximum amount of water that can be withdrawn from the lake is represented by the following formula:

V = V_{in}+V_{p}-V_{e}-V_{out} (Eq. 1)

Where:

V - Available amount of water for water supply in the Triangle area, measured in cubic feet per year.

V_{in} - Inflow amount of water, measured in cubic feet per year.

V_{out} - Amount of water released for the benefit of fish and downstream water users, measured in cubic feet per year.

V_{p} - Amount of water due to precipitation, measured in cubic feet per year.

V_{e} - Amount of evaporated water, measured in cubic feet per year.

Then, we can expand this expression as follows:

V = f_{in}\cdot \Delta t+h_{p}\cdot A_{l}-h_{e}\cdot A_{l}-f_{out}\cdot \Delta t

V = (f_{in}-f_{out})\cdot \Delta t +(h_{p}-h_{e})\cdot A_{l} (Eq. 2)

Where:

f_{in} - Average watershed inflow, measured in cubic feet per second.

f_{out} - Average flow to be released, measured in cubic feet per second.

\Delta t - Yearly time, measured in seconds per year.

h_{p} - Change in lake height due to precipitation, measured in feet per year.

h_{e} - Change in lake height due to evaporation, measured in feet per year.

A_{l} - Surface area of the lake, measured in square feet.

If we know that f_{in} = 900\,\frac{ft^{3}}{s}, f_{out} = 300\,\frac{ft^{3}}{s}, \Delta t = 31,536,000\,\frac{second}{yr}, h_{p} = 32\,\frac{in}{yr}, h_{e} = 55\,\frac{in}{yr} and A_{l} = 47,000\,acres, the available amount of water for supply purposes in the Triangle area is:

V = \left(900\,\frac{ft^{2}}{s}-300\,\frac{ft^{3}}{s} \right)\cdot \left(31,536,000\,\frac{s}{yr} \right) +\left(32\,\frac{in}{yr}-55\,\frac{in}{yr} \right)\cdot \left(\frac{1}{12}\,\frac{ft}{in}\right)\cdot (47000\,acres)\cdot \left(43560\,\frac{ft^{2}}{acre} \right)V = 1.464\times 10^{10}\,\frac{ft^{3}}{yr}

The lake can withdraw a maximum of 1.464\times 10^{10} cubic feet per year to provide water supply for the Triangle area.

5 0
3 years ago
Which type of muscle tissue is both voluntary and striated?
Elena L [17]

Answer:

Skeletal muscle

Explanation:

These classifications describe three distinct muscle types: skeletal, cardiac and smooth. Skeletal muscle is voluntary and striated, cardiac muscle is involuntary and striated, and smooth muscle is involuntary and non-striated.

4 0
4 years ago
Read 2 more answers
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