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3 years ago

The area of a square is 324 cm squared. what is the side length of the square?

Mathematics

1 answer:

alina1380 [7]3 years ago

7 0

All sides are 18 cm. You can figure this out by finding the square root of 324

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Which table identifies the one-sided and two-sided limits of function at x = 2?

Yuliya22 [10]

Answer:

Table 3

Step-by-step explanation:

Check table three;

$lim\:_{x\to \:2^-}\:f\left(x\right)=\:4$

$lim\:_{x\to \:2^+}\:f\left(x\right)=\:1$

Since the left hand limit $(lim\:_{x\to \:2^-}\:f\left(x\right))$ is not equal to the right hand limit $(lim\:_{x\to \:2^+}\:f\left(x\right))$ , the limit as x approaches to 2 does not exist.

Therefore "nonexistent" is true, and table 3 is the correct model of the limits of the function at x = 2

6 0

3 years ago

An architect draws a blueprint of a house. He draws the living room on the blueprint as 4.5 in. long by 6 in. wide with a scale

s2008m [1.1K]

Answer:

the answer is 8.5

Step-by-step explanation:

yeet

8 0

3 years ago

Read 2 more answers

Annie is framing a photo with a length of 6 inches and a width of 4 inches. The distance from the edge of the photo to the edge

Ede4ka [16]

Answer:

Part a) The quadratic function is $4x^{2} +20x-39=0$

Part b) The value of x is $1.5\ in$

Part c) The photo and frame together are $7\ in$ wide

Step-by-step explanation:

Part a) Write a quadratic function to find the distance from the edge of the photo to the edge of the frame

Let

x----> the distance from the edge of the photo to the edge of the frame

we know that

$(6+2x)(4+2x)=63\\24+12x+8x+4x^{2}=63\\ 4x^{2} +20x+24-63=0\\4x^{2} +20x-39=0$

Part b) What is the value of x?

Solve the quadratic equation $4x^{2} +20x-39=0$

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem

we have

$4x^{2} +20x-39=0$

$a=4\\b=20\\c=-39$

substitute in the formula

$x=\frac{-20(+/-)\sqrt{20^{2}-4(4)(-39)}} {2(4)}$

$x=\frac{-20(+/-)\sqrt{1,024}} {8}$

$x=\frac{-20(+/-)32} {8}$

$x=\frac{-20(+)32} {8}=1.5\ in$ -----> the solution

$x=\frac{-20(-)32} {8}=-6.5\ in$

Part c) How wide are the photo and frame together?

$(4+2x)=4+2(1.5)=7\ in$

5 0

3 years ago

Restrictions for 9/2x, 5x/8

brilliants [131]

Answer: hummmm let me think it is 14x 40x

Step-by-step explanation:

8 0

3 years ago

Simplify this expression -6w + (-8) + 1+ (-7w)

Rzqust [24]

Answer:

$\boxed{-6w+(-8)+1+(-7w)=-13w-7}$

Step-by-step explanation:

The given expression is $-6w+(-8)+1+(-7w)$ .

This expression is the same as;

$-6w+-8+1+-7w$ .

$-6w-8+1-7w$ .

We regroup the terms to obtain;

$-6w-7w-8+1$

We simplify to get

$-13w-7$

3 0

3 years ago

Read 2 more answers