Question

Jaxon is flying a kite, holding his hands a distance of 3.25 feet above the ground and letting all the kite’s strings play out. He measures the angle of elevation from his hand to the kite to be 24∘. If the string from the kite to his hand is 105 feet long, how many feet is the kite above the ground? Round your answer to the nearest tenth of a foot if necessary.

Answer 1

Answer: 46.0 ft

Step-by-step explanation:

$\sin 24^{\circ}=\frac{x}{105}\\\\x=105\sin 24^{\circ}$

So, the distance above the ground is $105\sin 24^{\circ}+3.25 \approx \boxed{46.0 \text{ ft}}$