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grin007 [14]
2 years ago
12

Study the velocity vs. time graph shown.

Physics
1 answer:
Gennadij [26K]2 years ago
3 0
8m is the answer :D your welcome
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An elevator lifts a total mass of 1.1×103 kg a distance of 40.0 m in 12.5 s. How much power does the elevator deliver?
Harman [31]

The power delivered by the elevator is 34496 W.

<h3>What is power?</h3>

Power is the rate at which energy is used up.

To calculate the power delivered by the elevator, we use the formula below.

Formula:

  • P = mgh/t.............. Equation 1

Where:

  • P = Power delivered by the elevator
  • m = Total mass on the elevator
  • g = acceleration due to gravity
  • h = Height

From the question,

Given:

  • m = 1.1×10³ kg
  • h = 40 m
  • t = 12.5 s
  • g = 9.8 m/s²

Substitute these values into equation 1

  • P = 1.1×10³×40×9.8/12.5
  • P = 34496 W.

Hence, the power delivered by the elevator is 34496 W.

Learn more about power here: brainly.com/question/24858512

#SPJ1

8 0
2 years ago
A wagon is rolling forward on level ground. Friction is negligible. The person sitting in the wagon is holding a rock. The total
Rudik [331]

Answer:

a) 0.41 m/s

b) 0.51 m/s

Explanation:

(a)

M = total mass of wagon, rider and the rock = 93.1 kg

V = initial velocity of wagon = 0.456 m/s

m = mass of the rock = 0.292 kg

v = velocity of rock after throw = 15.4 m/s

V' = velocity of wagon after rock is thrown

Using conservation of momentum

M V = m v + (M - m) V'

(93.1) (0.456) = (0.292) (15.4) + (93.1 - 0.292) V'

V' = 0.41 m/s

b)

M = total mass of wagon, rider and the rock = 93.1 kg

V = initial velocity of wagon = 0.456 m/s

m = mass of the rock = 0.292 kg

v = velocity of rock after throw = - 15.4 m/s

V' = velocity of wagon after rock is thrown

Using conservation of momentum

M V = m v + (M - m) V'

(93.1) (0.456) = (0.292) (- 15.4) + (93.1 - 0.292) V'

V' = 0.51 m/s

6 0
4 years ago
28 points!! please help
kobusy [5.1K]
7(a) transpiration is faster in warmer dry air
(b)(I)xylem
(ii) 1. They are stacked end-to-end
2. Consists of dead cells
8 0
3 years ago
A radiographer stands six feet from the x-ray source when performing a portable chest exam and receives an exposure of 2 mGy. If
telo118 [61]

Answer:

  I₂ = 8 mG

Explanation:

The intensity of a beam is

          I = P / A

Where P is the emitted power which is 3) 3

           

Let's use index 1 for the initial position of r₁ = 6 ft and 2 for the second position r₂ = 3 ft

          I₁ A₁  = I₂  A₂

           I₂ = I₁ A₁ / A₂

The area of ​​the beam if we assume that it is distributed either in the form of a sphere is

           A₁ = 4π r²

We substitute

            I₂ = I₁ (r₁ / r₂)²

           I₂ = 2 (6/3)²

           I₂ = 2 4

           I₂ = 8 mG

3 0
3 years ago
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which statement correctly describes the relationship between a black body radioterapia it’s tmeptaute and the electromagnic radi
jasenka [17]
It’s A if there’s multiple choices
7 0
3 years ago
Read 2 more answers
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