Study the velocity vs. time graph shown.

A satellite with mass 6000 kg is orbiting the planet at 2500 km above the planet's

9966 [12]

By the law of universal gravitation, the gravitational force F between the satellite (mass m) and planet (mass M) is

F = G M m / R ²

where

• G = 6.67 × 10⁻¹¹ m³/(kg•s²) is the universal gravitation constant

• R = 2500 km + 5000 km = 7500 km is the distance between the satellite and the center of the planet

Solve for M :

M = F R ² / (G m)

M = ((3 × 10⁴ N) (75 × 10⁵ m)²) / (G (6 × 10³ kg))

M ≈ 2.8 × 10¹⁴ kg

6 0

2 years ago

Why do you think spiders are disliked

SCORPION-xisa [38]

Answer:

it is called arachnophobia

Explanation:

most reason are they way they walk and jump and the people who know they have 4 eyes

Hope This Helped i Like Spiders (^^vv^^) (spider smiley face)

4 0

1 year ago

Read 2 more answers

A miner of mass 90kg travels down a slide calculate the potential energy of the miner when he moves15m vertically downwards

Lena [83]

Answer:

Gravitational Potential Energy = mgh

Explanation:

As the miner moves down, the GPE changes because the height changes.

Gravitational Potential Energy = mgh

8 0

2 years ago

When the electron in a hydrogen atom moves from n = 6 to n = 1, light with a wavelength of ________ nm is emitted?

Oduvanchick [21]

First we find the energy level with the following formula, where a is the energy level, n1 is the final energy level, n2 is the starting energy level and r is Rydberg's constant in Joules
$a = r \times ( \frac{1}{n1} - \frac{1}{n2} )$
We insert the values

$a = 2.18 \times {10}^{ - 18} \times ( \frac{1}{ {1}^{2} } - \frac{1}{ {6}^{2} } )$
$= 2.12 \times {10}^{ - 18}$
The wavelength is found with this formula, where h is Planck's constant and c is the speed of light
$wavelength = \frac{h \times c}{a}$
Finally we insert the values
$\frac{6.626 \times {10}^{ - 34} \times 3 \times {10}^{8} }{2.12 \times {10}^{ - 18} } = 9.376 \times {10}^{ - 8}$
Which is the same as 93.8 nm

3 0

2 years ago

A diagram of a closed circuit with a power source on the left labeled 6 V. There are 3 resistors in parallel, separate paths, co

AfilCa [17]

Answer:

Current: 1.0 Amperes

The minimum current is flowing through path D

Explanation:

We first find the equivalent resistance to the three resistors in parallel ( which is the total resistance of the circuit) via the equation:

$\frac{1}{R_e} =\frac{1}{R_B}+\frac{1}{R_C}+\frac{1}{R_D}\\\frac{1}{R_e} =\frac{1}{10}+\frac{1}{20}+\frac{1}{50}=0.17\\R_e=(1/0.17)\Omega\\R_e=5.88 \Omega$

with this info, we can estimate the current going through branch A using Ohm's Law, and the information that the power source is 6 V:

$V=I*R\\6V=I*5.88\Omega\\I=\frac{6}{5.88} Amp\\I=1.02A$

where the current comes in units of Amperes since all other the quantities are given in the SI system, and we can round this answer to 1.0 Amp following the request to round it to the tenth.

The current will be the lowest through the branch with the largest resistor due to the fact that less current will flow through the path of more resistance.

Than means that the lowest current will be registered through branch D where the 50 $\Omega$ resistor is.

8 0

2 years ago

Read 2 more answers