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Lapatulllka [165]
2 years ago
14

The water in this pot is in the process of changing from a liquid to a gas. Thermal energy is still being added to the water as

it vaporizes, but its temperature and the motion of its particles are not increasing. What do you think is happening to the extra energy?
​
Physics
1 answer:
olga nikolaevna [1]2 years ago
6 0

The extra energy allows the molecules to convert states of molecules.

<h3>What is heating?</h3>

When the temperature is increased , the body or particle is said to be heating.

The water in this pot is in the process of changing from a liquid to a gas. Thermal energy is still being added to the water as it vaporizes, but its temperature and the motion of its particles are not increasing.

When the liquid is converted to gas, the temperature reaches the boiling point of water. After boiling, the heat added up will only make the particles to convert its phase and go away in then atmosphere.

Thus, extra energy added helps molecules of water to change its state from liquid to solid.

Learn more about heating.

brainly.com/question/1429452

#SPJ1

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Omar rubs a balloon with wool, giving the balloon a
CaHeK987 [17]

Answer:

-8.9×10-14=-89-14=-103°C

25°C=2km

-103°C=? Less

=-103/25×2km

=-8.24km

3 0
3 years ago
1. El puente mas largo del mundo es el puente Akashi Kaikyo, en Japón. El puente mide 3910 m de largo y está construido con acer
bearhunter [10]

Answer:

It's 1.0000042 times longer in summer than in winter. It represents a 1.6 centimeters difference between seasons.

Explanation:

The linear coefficient of thermal expansion for steel is about 1.2*10^{-7}\°C^{-1}. From the equation of linear thermal expansion, we have:

L_f=L_0(1+\alpha\Delta T)

Taking the winter day as the initial, and the summer day as the final, we can take the relationship between them:

L_{summer}=L_{winter}[1+(1.2*10^{-7}\°C^{-1})(30\°C+5\°C)]\\\\L_{summer}=(1.0000042)L_{winter}

It means that the bridge is 1.0000042 times longer in summer than in winter. If we multiply it by the length of the bridge, we obtain that the difference is of about 1.6 centimeters between the two seasons.

8 0
4 years ago
Determine the velocity (in m/s) of the object at 10seconds. Include a numerical answer accurate to the first decimal place. If n
tatuchka [14]

Answer:

v = 0.5 [m/s]

Explanation:

In order to determine the speed in such a time interval, we must calculate the slope between the last two positions.

The slope of a line is determined by the following mathematical expression.

P₂ = point 2 = (12,12) = (x₂,y₂)

P₁ = Point 1 = (6,9) = (x₁,y₁)

In this specific case, we must see that in the x-axis we have time, and on the y-axis, we have the space axis.

Now using the slope:

m =\frac{y_{2} -y_{1} }{x_{2} -x_{1} } \\m = \frac{12-9}{12-6}\\m = 0.5

This slope is equal to the speed (velocity)

v = 0.5 [m/s]

8 0
3 years ago
an object has 5.00 kg*m/s of momentum. if you double the mass and double the velocity, how much momentum would it have PLEASE HE
KIM [24]

The final momentum is 20.00 kg*m/s

Explanation:

The momentum of an object is given by:

p=mv

where

m is the mass of the object

v is its velocity

For the object in the problem, the initial momentum is

p=mv=5.00 kg m/s

Then, the mass is doubled:

m' = 2m

And the velocity is also doubled:

v' = 2v

So, the new momentum will be:

p'=m'v'=(2m)(2v)=4(mv) = 4p = 4(5.00)=20 kg m/s

So, the final momentum is 4 times the initial momentum.

Learn more about momentum:

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6 0
4 years ago
If a train going 60 m/s hits the brakes, and it takes the train 85 seconds to stop, what is
Anvisha [2.4K]

Question :-

  • If a Train going with 60 m/s Speed hits the Brakes, and takes 85 sec to stop. What is the Acceleration of the Train ?

Answer :-

  • Acceleration of Train is 0.70 m/s² .

Explanation :-

As per the provided information in the given question, we have been given that the Speed of the Train is 60 m/s . Time taken to stop the Train is 85 sec . And, we have been asked to calculate the Acceleration of the Train .

For calculating the Acceleration , we will use the Formula :-

\bigstar \:  \:  \:  \boxed { \sf{ \: Acceleration \:  =  \:  \dfrac{v \:  -  \: u}{t} \:  }} \\

Where ,

  • V denotes to Final Velocity .
  • U denotes to Initial Velocity .
  • T denotes to Time Taken .

Therefore , by Substituting the given values in the above Formula :-

\dag \:  \:  \:  \:  \sf{Acceleration \:  =  \:  \dfrac{Final  \: Velocity \:  -  \: Initial \: Velocity}{Time} } \\

\longmapsto \:  \:  \: \sf{Acceleration \:  =  \:  \dfrac{0 \:  -  \: 60}{85} } \\

\longmapsto \:  \:  \: \sf{Acceleration \:  =  \:  \dfrac{60}{85} } \\

\longmapsto \:  \:  \: \textbf {\textsf {Acceleration \:  =  \: 0.70 }}

Hence :-

  • Acceleration = 0.70 m/s² .

\underline {\rule {210pt} {4pt}}

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7 0
2 years ago
Read 2 more answers
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