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3 years ago

A change in color during a reaction is often a sign that a chemical change has occurred.

Physics

2 answers:

Inga [223]3 years ago

5 0

<h3><u>Answer;</u></h3>

The above statement is <u>True</u>;

A change in color during a reaction is often a sign that a chemical change has occurred.

<h3><u>Explanation</u>;</h3>

A change in color indicates the occurrence of a chemical change. This means a chemical reaction is occurring. The rearrangement of electrons between substances results in new substances being formed.
Additionally, changes in color, formation of a precipitate, temperature change or a change in pH also indicate the occurrence of a chemical reaction.

guajiro [1.7K]3 years ago

3 0

True, also fizzing and heat being released

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The graph of the relationship between the volume of a gas at constant temperature and its pressure is a(n)?

timurjin [86]

<span>When the difference between two results is larger than the estimates error, the result is</span>

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2 years ago

The most recently discovered system close to Earth is a pair of brown dwarfs known as Luhman 16. It has a distance of 6.5 light-

just olya [345]

Answer:

1.99 parsecs.

Explanation:

We have been given that the most recently discovered system close to Earth is a pair of brown dwarfs known as Luhman 16. It has a distance of 6.5 light-years.

We know that one light year equals to 0.306601 parsecs. To convert 6.5 light-years to parsecs, we will multiply 0.306601 by 6.5.

$6.5\text{ Light-years}=6.5\times 0.306601\text{ Parsecs}$

$6.5\text{ Light-years}=1.9929065\text{ Parsecs}$

$6.5\text{ Light-years}\approx 1.99\text{ Parsecs}$

Therefore, Luhman 16 is approximately 1.99 parsecs away from the Earth.

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3 years ago

A car accelerates in the +x direction from rest with a constant acceleration of a1 = 1.62 m/s2 for t1 = 20 s. At that point the

arsen [322]

Total displacement of the car: 405 m

Explanation:

The first part of the motion of the car is a uniformly accelerated motion, so we can use the suvat equation

$s_1=ut_1+\frac{1}{2}a_1 t_1^2$

where:

u = 0 is the initial velocity (the car starts from rest)

$t_1 = 20 s$ is the time elapsed in the 1st part

$a_1=1.62 m/s^2$ is the acceleration of the car in the 1st part

$s_1$ is the displacement of the car in the 1st part

Solving for $s_1$ ,

$s_1=0+\frac{1}{2}(1.62)(20)^2=324 m$

We can also find the velocity of the car after these 20 seconds using the equation:

$v_1 = u +a_1 t_1 = 0 + (1.62)(20)=32.4 m/s$

Now we can find the distance covered by the car in the 2nd part, where it decelerates after having seen the tree limb on the road. We can do it by using the suvat equation:

$s_2 = (\frac{v_1 + v_2}{2})t_2$