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vodomira [7]
3 years ago
13

5. During an anti-bullying club meeting after school, a student mentions that a new student has joined your class at school. The

individual wears clothes that are not very common at your school and are religious in nature. Some of the other students have been talking negatively about the new student.
a. How can this scenario lead to bullying?


b. How should the club advise students to respond in this situation?


c. How will the advice help prevent potential bullying in this situation
Physics
1 answer:
Oksana_A [137]3 years ago
5 0

Answer:

a. Constant gossiping, and talking negative about a student could cause them to feel very very ill about their beliefs, their familly, school, clothes, etc. this  scenario will make the student feel alienated.

b. The club should advise the students that they should not participate in these talks, allow them into their groups, and should try to talk people out of those conversations.

c. The advice will keep several kids pull away from talking negatively about the kid, help stop the ill intended gossip, and hopefully make them feel better.

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Help please i will mark brainlist!!
Dmitrij [34]
The answer is A.


p=m/v
p= 240/60
p= 4 g/cm^3
7 0
3 years ago
Read 2 more answers
A small block of mass 20.0 grams is moving to the right on a horizontal frictionless surface with a speed of 0.68 m/s. The block
Usimov [2.4K]

Answer:

a) v'=-0.227\ m.s^{-1}

b) v=1.36\ m.s^{-1}

Explanation:

Given:

mass of the lighter block, m'=0.02\kg

velocity of the lighter block, u'=0.68\ m.s^{-1}

mass of the heavier block, m=0.04\ kg

velocity of the heavier block, u=0\ m.s^{-1}

a)

Using conservation of linear momentum:

m'.u'+m.u=m'.v'+m.v

where:

v'= final velocity of the lighter block

v= final velocity of the heavier block

m'.u'=m'.v'+m.v

m'(u'-v')=m.v ........................(1)

Since kinetic energy is conserved in elastic collision:

\frac{1}{2}m'.u'^2=\frac{1}{2}m'.v'^2+\frac{1}{2}m.v^2

m'(u'^2-v'^2)=m.v^2

m'(u'-v')(u'+v')= m.v^2

divide the above equation by eq. (1)

v=u'+v' .............................(2)

now we substitute the value of v from eq. (2) in eq. (1)

m'(u'-v')=m(u'+v')

\frac{m'+m}{m'-m} =\frac{u'}{v'}

\frac{0.02+0.04}{0.02-0.04} =\frac{0.68}{v'}

v'=-0.227\ m.s^{-1} (negative sign denotes that the direction is towards left)

b)

now we substitute the value of v' from eq. (2) in eq. (1)

m'(u'-v+u')=m.v

2m'.u'=(m-m')v

2\times 0.02\times 0.68=(0.04-0.02)\times v

v=1.36\ m.s^{-1}

6 0
3 years ago
A 300-kg piano being held by a crane is accidentally dropped from a height of 15 meters. a. What is the speed of the piano just
FinnZ [79.3K]

Answer:

a) 17.16m/s

b) 44,145J

c) Sound the piano makes when hitting the ground, vibration of the ground, heat.

d) i) It's smaller due to the energy dissipated by the friction between air and the parachute.

ii) It stays the same, the only difference is that the dissipated energy is distributed between air resistance and the kinetic energy dissipated by the ground whent he piano hits it.

Explanation:

a)

In order to solve this problem we must start by doing a drawing of the situation, which will help us visualize the problem better. (See attached picture).

So, in this problem we can ignore air resistance so we can say that the energy is conserved, this is the total initial energy is the same as the total final energy, so we get that:

U_{0}+K_{0}=U_{f}+K_{f}

When the piano is released it has an initial speed of zero, so the initial kinetic energy is zero. When the piano hits the ground it will have a height of 0m, so the final potential energy is zero as well. This will simplify our equation:

U_{0}=K_{f}

We know that potential energy is given by the formula:

U=mgh

and kinetic energy is given by the formula:

K=\frac{1}{2}mv^{2}

which can be substituted in our equation:

mgh=\frac{1}{2}mv^{2}

we can divide both sides of the equation into the mass of the piano, so we get:

gh=\frac{1}{2}v^{2}

which can be solved for the final velocity which yields:

v=\sqrt{2gh}

we can now substitute the data provided by the problem so we get:

v=\sqrt{2(9.81m/s^{2})(15m)}

which yields:

v=17.16m/s

b)

Since energy is conserved, this means that the total dissipated energy will be the same as the potential energy, so we get that:

E=mgh

so

E=(300kg)(9.81m/s^{2})(15m)

which yields:

E=44,145J

c)

When the piano hits the ground, the kinetic energy it had will be transformed to other types of energy, mostly vibration and heat. The vibration will turn to sound due to the movement of air created by the piano itself and the ground. And heat is created by the friction between the molecules created by the vibrations and the collition itself. So some of the indicators of this release of energy could be:

-Sound

-Vibration

-Heat.

d)

i) The amount of inetic energy dissipated would decrease due to the friction between air and the parachute. Since air is resisting the movement of the piano, this will translate into a loss of energy, if we did an energy balance we would get that:

U_{0}=K_{f}+E_{p}

The total amount of energy is conserved but it will be distributed between the energy lost due to air resistance and the kinetic energy the piano has at the time it hits the ground.

ii) So the total amount of energy dissipated remains the same, the only difference is that it will be distributed between air resistance and the kinetic energy of the piano.

3 0
4 years ago
Monochromatic coherent light shines through a pair of slits. If the wavelength of the light is decreased, which of the following
Law Incorporation [45]

Answer:

he correct answers are a, b

Explanation:

In the two-slit interference phenomenon, the expression for interference is

          d sin θ= m λ                       constructive interference

          d sin θ = (m + ½) λ             destructive interference

in general this phenomenon occurs for small angles, for which we can write

           tanθ = y / L

           tan te = sin tea / cos tea = sin tea

           sin θ = y / La

un

derestimate the first two equations.

Let's do the calculation for constructive interference

         d y / L = m λ

the distance between maximum clos is and

         y = (me / d) λ

this is the position of each maximum, the distance between two consecutive maximums

         y₂-y₁ = (L   2/d) λ - (L 1 / d) λ₁          y₂ -y₁ = L / d λ

examining this equation if the wavelength decreases the value of y also decreases

the same calculation for destructive interference

         d y / L = (m + ½) κ

         y = [(m + ½) L / d] λ

again when it decreases the decrease the distance

the correct answers are a, b

7 0
3 years ago
What is a homopolar motor?????)
PSYCHO15rus [73]

Answer:

A homopolar motor is a direct current electric motor with two magnetic poles, the conductors of which always cut unidirectional lines of magnetic flux by rotating a conductor around a fixed axis so that the conductor is at right angles to a static magnetic field.

Explanation:

7 0
3 years ago
Read 2 more answers
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