Answer:
g = g₀ [1- 2 h / Re + 3 (h / Re)²]
Explanation:
The law of universal gravitation is
F = G m Me / Re²
Where g is the universal gravitational constant, m and Me are the mass of the body and the Earth, respectively and R is the distance between them
F = G Me /Re² m
We call gravity acceleration a
g₀ = G Me / Re².
When the body is at a height h above the surface the distance is
R = Re + h
Therefore the attractive force is
F = G Me m / (Re + h)²
Let's take Re's common factor
F = G Me / Re² m / (1+ h / Re)²
As Re has a value of 6.37 10⁶ m and the height of the body in general is less than 10⁴ m, the h / Re term is very small, so we can perform a series expansion
(1+ h / Re)⁻² = 1 -2 h / Re + 6/2 (h / Re) 2 + ...
Let's replace
F = G Me /Re² m [1- 2 h / Re + 3 (h / Re)²]
F = g₀ m [1- 2 h / Re + 3 (h / Re)²]
If we call the force of attraction at height
m g =g₀ m [1- 2 h / Re + 3 (h / Re)²]
g = g₀ [1- 2 h / Re + 3 (h / Re)²]
Explanation:
Below is an attachment containing the solution.
These are the most common type of faults not just inductors but also with other elements too like resistors,transformers, generators etc.
open circuit fault means the flow of current is disrupted some how in the circuit and the circuit stops operating. and for short circuit fault the current in the system will be pretty high and this short circuit current or fault current will always run back to the fault location, if the inductor got short circuited somehow then the fault current will only run through it because it will then provide a very low impedence path
Explanation:
Doing homework is risky behaviour broo
The sound wave will have traveled 2565 m farther in water than in air.
Answer:
Explanation:
It is known that distance covered by any object is directly proportional to the velocity of the object and the time taken to cover that distance.
Distance = Velocity × Time.
So if time is kept constant, then the distance covered by a wave can vary depending on the velocity of the wave.
As we can see in the present case, the velocity of sound wave in air is 343 m/s. So in 2.25 s, the sound wave will be able to cover the distance as shown below.
Distance = 343 × 2.25 =771.75 m
And for the sound wave travelling in fresh water, the velocity is given as 1483 m/s. So in a time interval of 2.25 s, the distance can be determined as the product of velocity and time.
Distance = 1483×2.25=3337 m.
Since, the velocity of sound wave travelling in fresh water is greater than the sound wave travelling in air, the distance traveled by sound wave in fresh water will be greater.
Difference in distance covered in water and air = 3337-772 m = 2565 m
So the sound wave will have traveled 2565 m farther in water than in air.
