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Juliette [100K]
2 years ago
8

Derive that efficiency is the ratio of output and input work.​

Physics
2 answers:
Stels [109]2 years ago
8 0

Answer:

The efficiency of a simple machine is defined as the ratio of useful work done by a machine (output work) to the total work put into the machine (input work). For ideal or perfect machine, work output is equal to the work input.

Explanation:

Hope it Helps!!!

spayn [35]2 years ago
4 0

Answer:

efficiency of a simple machine is defined as the ratio of useful work done by a machine (output work) to the total work put into the machine (input work). For ideal or perfect machine, work output is equal to the work input.

Explanation:

hope it will help you

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Magnetism is the product of a moving charged particle. We can have electricity without magnetism but we can not have magnetism without electricity.An electro magnet is made so that we have a soft metal core and electricity around it. A bar magnet is a normal magnet in bar shape with permanent magnetism.
6 0
3 years ago
How does the phrase studying grammar function in sentence 4? A) main verb B) direct object C) subject complement D) subject of t
lisabon 2012 [21]

Answer: (b) direct object

Explanation:

6 0
3 years ago
Read 2 more answers
As the hot gas from a space shuttle is released downward, what does this cause to happen?
andrew11 [14]

Answer:

D. Upward force on the shuttle

Explanation:

The hot gas from space shuttles released downward causes an upward force on the shuttle and propels it up the more.

  • This hot gas is produced from super cooled oxygen and hydrogen tanks within the shuttle.
  • The upward force on the shuttle allows the craft to escape the gravitational pull of the earth on the shuttle
  • Special level of rapid acceleration must be attained for the shuttle to escape the earth pull.
8 0
2 years ago
A 15.0 cm object is 12.0 cm from a convex mirror that has a focal length of -6.0 cm. What is the height of the image produced by
Vlad [161]

Answer: D. 5cm

Explanation:

Given the following :

Focal length (f) = - 6.0 cm

Height of object = 15.0cm

Distance of object from mirror (u) = 12.0cm

Height of image produced by the mirror =?

Firstly, we calculate the distance of the image from the mirror.

Using the mirror formula

1/f = 1/u + 1/v

1/v = 1/f - 1/u

1/v = 1/-6 - 1/12

1/v = - 1/6 - 1/12

1/v = (- 2 - 1) / 12

1/v = - 3 / 12

v = 12 / - 3

v = - 4

Using the relation :

(Image height / object height) = (- image distance / object distance)

Image height / 15 = - (-4) / 12

Image height / 15 = 4 / 12

Image height = (15 × 4) / 12

Image height = 60 / 12

Image height = 5cm

6 0
3 years ago
In a very busy off-campus eatery one chef sends a 201 g broccoli-tomato-pickle-onion-mushroom pizza sliding down the counter fro
Murrr4er [49]

Answer:

The correct answer is:

(A) to the left

(B) at speed -0.8725 m/s

Explanation:

The given values are:

Plate 1:

Mass,

m₁ = 201 g

Velocity,

v₁ = +1.79 m/s

Plate 2:

Mass,

m₁ = 335 g

Velocity,

v₁ = -2.47 m/s

According to the conservation of momentum, we get

⇒  m_1v_1+m_2v_2=(m_1+m_2)v

then,

⇒  v=\frac{m_1v_1+m_2v_2}{m_1+m_2}

On substituting the values, we get

⇒     =\frac{201\times 1.79+335\times (-2.47)}{201+335}

⇒     =\frac{359.79-827.45}{536}

⇒     =\frac{-467.66}{536}

⇒     =-0.8725 (to the left)

3 0
2 years ago
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