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Salsk061 [2.6K]
2 years ago
10

You have now identified whether crabs are able to see plankton they eat near the ocean floor. Based on your answer, explain how

this information can be used to help the Australian Institute of Marine Biology further to understand the environment of the ocean floor (what other organisms live at the bottom? How are these able to see their food/ attract food to survive?
Chemistry
1 answer:
Murrr4er [49]2 years ago
7 0

They are able to find out more organisms which are present at the bottom of the sea due to their accomplishment.

<h3>How this information can be used to help to understand the environment of the ocean floor?</h3>

This information can be used to help the Australian Institute of Marine Biology further to understand the environment of the ocean floor because they are able to see the seas floor and can find out other creatures as well.

So we can conclude that they are able to find out more organisms which are present at the bottom of the sea due to their accomplishment.

Learn more about crabs here: brainly.com/question/1120881

#SPJ1

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When 11.12 g of neon is combined in a 100 L container at 80oC with 9.59 g of argon, what is the mole fraction of argon?
PolarNik [594]
The correct answer for the question that is being presented above is this one: "<span>0.3."

Here it is how to solve.
M</span><span>olecular mass of Ar = 40
</span><span>Molecular mass of Ne = 20
</span><span>Number of moles of Ar = 9.59/40 = 0.239
</span><span>Number of moles of Ne = 11.12/20= 0.556
</span><span>Mole fraction of argon = 0.239/ ( 0.239 + 0.556) = 0.3</span><span>
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3 0
3 years ago
19)Calculate the number of moles of Al2O3 that are produced when 15 mol of Fe is produced
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Answer:

C

Explanation:

Calculate the number of moles of Al2O3 that are produced when 15 mol of Fe is produced

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2 years ago
Using the appropriate starting material, (1) show the synthetic steps of the modified Kiliani-Fischer chain extension synthesis
sashaice [31]

Answer:............

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Explanation:

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3 0
3 years ago
A 0.75M solution of CH3OH is prepared in 0.500 kg of water. How many moles of CH3OH are needed?
4vir4ik [10]

Answer:

We need 0.375 mol of CH3OH to prepare the solution

Explanation:

For the problem they give us the following data:

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Mass of Solvent is 0,5Kg

knowing that the density of water is 1g / mL,  we find the volume of water:

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Now, find moles of CH_{3} OH are needed using the molarity equation:

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therefore the solution is prepared using 0.5 L of H2O and 0.375 moles of CH3OH,  resulting in a concentration of 0,75M

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