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Harlamova29_29 [7]
2 years ago
15

An astronaut on the moon places a package on a scale and finds its weight to be 10. N. () What would the weight of the package

be on the earth?
(b) What is the mass of the package on the moon?
(c) What is the package’s mass on earth?
Physics
1 answer:
jeka942 years ago
8 0

Answer:

(a) 61.25 N

(b) 6.25 kg

(c) 6.25 Kg

Explanation:

Weight on moon = 10 N

Acceleration due to gravity on moon = 1.6 m/s^2

Acceleration due to gravity on earth = 9.8 m/s^2

Let m be the mass of the package.

(a) Weight on earth = mass x acceleration due to gravity on earth

Weight on earth = 6.25 x 9.8 = 61.25 N

(b) Weight on moon = mass x acceleration due to gravity on moon

10 = m x 1.6

m = 6.25 kg

(c) Mass of the package remains same as mass does not change, so the mass of package on earth is 6.25 kg.

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You biked to the store in 10 minutes. The store was 3 km away. What was your average speed?
sineoko [7]

Answer:

speed in km/min:

0.3km/min

speed in km/h:

18km/h

speed in m/s:

5m/s

Explanation:

the average speed is defined as:

s=\frac{d}{t}

where s is the speed, d is the distance traveled, and t is the time

according to the statement:

d=3km = 3,000m

and

t=10min=\frac{1}{6}h=600s (10 minutes are equal to a sixth of an hour which is 600 seconds)

Because the units in which the speed is required are not indicated, here are some options for the answer:

Depending on the units in which you need the speed, are the quantities you should use.

Speed in km / h (kilometers per hour):

s=\frac{3km}{\frac{1}{6}h }\\ \\s=18km/h

speed in m / s (meters per second):

s=\frac{3,000m}{600s}\\ s=5m/s

or the speed in km/min (kilometers per minute)

s=\frac{3km}{10min}\\ s=0.3km/min

4 0
3 years ago
The speed of sound waves
neonofarm [45]
B. Is faster in solids than liquids would be the correct answer because the molecules in solids are much closer and can pass along energy faster and more effectively.
4 0
2 years ago
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Murljashka [212]

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5 0
3 years ago
Tom kicks a soccer ball on a flat, level field giving it an initial speed of 20 m/s at an angle of 35 degrees above the horizont
SVEN [57.7K]

Answer:

(a) 2.34 s

(b) 6.71 m

(c) 38.35 m

(d) 20 m/s

Explanation:

u = 20 m/s, theta = 35 degree

(a) The formula for the time of flight is given by

T = \frac{2 u Sin\theta }{g}

T = \frac{2 \times 20 \times Sin35 }{9.8}

T = 2.34 second

(b) The formula for the maximum height is given by

H = \frac{u^{2} \times Sin^{2}\theta }{2g}

H = \frac{20^{2} \times Sin^{2}35 }{2 \times 9.8}

H  = 6.71 m

(c) The formula for the range is given by

R = \frac{u^{2} \times Sin 2\theta }{g}

R = \frac{20^{2} \times Sin 2 \times 35}{9.8}

R = 38.35 m

(d) It hits with the same speed at the initial speed.

8 0
3 years ago
a fan is rotating clockwise and its acceleration has a positive sign. is the angular velocity of the fan speeding up, slowing do
balu736 [363]

Answer:

The angular velocity is slowing down.

Explanation:

  • By convention, if a rigid body is rotating clockwise, the angular velocity is negative.
  • If the angular acceleration has a positive sign, since the angular acceleration and the angular velocity have opposite signs, this means that the angular velocity is slowing down.
5 0
2 years ago
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