Answer: 1.77 s
Explanation: In order to solve this problem we have to use the kinematic equation for the position, so we have:
xf= xo+vo*t+(g*t^2)/2 we can consider the origin on the top so the xo=0 and xf=29 m; then
(g*t^2)/2+vo*t-xf=0 vo is the initail velocity, vo=7.65 m/s
then by solving the quadratric equation in t
t=1.77 s
Answer:
4. 7.59276
Explanation:
Add up the x components:
Aₓ + Bₓ + Cₓ = 5 − 1.6 + 2.4 = 5.8
Add up the y components:
Aᵧ + Bᵧ + Cᵧ = -2.4 + 3.3 + 4 = 4.9
Use Pythagorean theorem to find the magnitude:
√(x² + y²)
√(5.8² + 4.9²)
√57.65
7.59276
Answer:
410 m
Explanation:
Given:
v₀ = 20.5 m/s
a = 0 m/s²
t = 20 s
Find: Δx
Δx = v₀ t + ½ at²
Δx = (20.5 m/s) (20 s) + ½ (0 m/s²) (20 s)²
Δx = 410 m
Explanation:
Coefficient of kinetic friction is the resistive force that opposes the motion of a body as it moves and is in contact with another body.
It is found by dividing the frictional force by the normal force.
- Friction is a force that opposes motion.
- Static friction is for bodies that are not in motion
- Kinetic friction is for moving bodies.
P=4800kgm/s
As
p=mΔv
where p is momentum, m is mass and v is velocity
Given values is
m =1200kg
Δv= 17m/s-13m/s=4m/s
Now
p=mΔv
p=(1200kg)*(4m/s)
p=4800kgm/s
