Which substance produces hydroxide ions in a solution

A sample of a compound is decomposed in the laboratory and produces 330 g carbon, 69.5 g hydrogen, and 220.2 g oxygen. Calculate

Zarrin [17]

Answer: Empirical formula is $C_2H_5O$

Explanation: We are given the masses of elements present in a sample of compound. To evaluate empirical formula, we will be following some steps.

Step 1 : Converting each of the given masses into their moles by dividing them by Molar masses.

$Moles=\frac{\text{Given mass}}{\text{Molar mass}}$

Molar mass of Carbon = 12.0 g/mol

Molar mass of Hydrogen = 1.0 g/mol

Molar mass of Oxygen = 16.0 g/mol

Moles of Carbon = $\frac{330g}{12g/mol}=27.5moles$

Moles of Hydrogen = $\frac{69.5g}{1g/mol}=69.5moles$

Moles of Oxygen = $\frac{220.2g}{16g/mol}=13.76moles$

Step 2: Dividing each mole value by the smallest number of moles calculated above and rounding it off to the nearest whole number value

Smallest number of moles = 13.76 moles

$\text{Mole ratio of Carbon}=\frac{27.5moles}{13.76moles}=1.99\approx 2$

$\text{Mole ratio of Hydrogen}=\frac{69.5moles}{13.76moles}=5.05\approx 5$

$\text{Mole ratio of Oxygen}=\frac{13.76moles}{13.76moles}=1$

Step 3: Now, the moles ratio of the elements are represented by the subscripts in the empirical formula

Empirical formula becomes = $C_2H_5O$

7 0

2 years ago

A compound with a total of four carbons. A straight chain across the bottom of three carbons with all single bonds. There is a m

AleksandrR [38]

I know the answer. It is 2 straight chains. lLOL

6 0

3 years ago

Iodine-131 is a beta emitter used as a tracer in radio immunoassays in biological systems. It follows first order kinetics. The

allsm [11]

Answer: The amount of Iodine-131 remain after 39 days is 0.278 grams

Explanation:

The equation used to calculate rate constant from given half life for first order kinetics:

$t_{1/2}=\frac{0.693}{k}$

where,

$t_{1/2}$ = half life of the reaction = 8.04 days

Putting values in above equation, we get:

$k=\frac{0.693}{8.04days}=0.0862days^{-1}$

Rate law expression for first order kinetics is given by the equation:

$k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}$

where,

k = rate constant = $0.0862days^{-1}$

t = time taken for decay process = 39 days

$[A_o]$ = initial amount of the sample = 8.0 grams

[A] = amount left after decay process = ?

Putting values in above equation, we get:

$0.0862=\frac{2.303}{39}\log\frac{8.0}{[A]}$

$[A]=0.278g$

Hence, the amount of Iodine-131 remain after 39 days is 0.278 grams

3 0

2 years ago

If you were sitting on a horse on a Merry-Go-Round do the horse revolve or rotate

Ganezh [65]

It would be Rotate..

7 0

3 years ago

Gaseous chlorine dioxide (ClO2) is used in bleaching flour and municipal water treatment in

trapecia [35]

Taking into account the ideal gas law, the pressure is 2.52 atm.

An ideal gas is a theoretical gas that is considered to be composed of randomly moving point particles that do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.

The pressure, P, the temperature, T, and the volume, V, of an ideal gas are related by a simple formula called the ideal gas law. This equation relates the three variables if the amount of substance, number of moles n, remains constant. The universal constant of ideal gases R has the same value for all gaseous substances. The numerical value of R will depend on the units in which the other properties are worked.

P×V = n×R×T

In this case, you know:

P=?
V= 500 L
n= 52.1 moles
R= 0.082 $\frac{atmL}{molK}$
T= 22 C= 295 K (being 0 C=273 K)

Replacing in the ideal gas law:

P×500 L = 52.1 moles ×0.082 $\frac{atmL}{molK}$ ×295 K

Solving:

P= (52.1 moles ×0.082 $\frac{atmL}{molK}$ ×295 K)÷ 500 L

P= 2.52 atm

Finally, the pressure is 2.52 atm.

Learn more about ideal gas law:

brainly.com/question/4147359?referrer=searchResults

5 0

2 years ago