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s2008m [1.1K]
2 years ago
7

The ground-state configuration of a negative ion of a halogen

Chemistry
1 answer:
mafiozo [28]2 years ago
5 0

Answer:

The ground state configuration for the negative ion of a halogen. ... A possible excited state electronic configuration. 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^10 4p^6 5s^1 6s^1. Its symbol is the double solid lin, // or ||, in a cell diagram.

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1. A room has dimensions 8.8 yd * 8.4 yd * 8.5 yd, what is its volume in L?
AveGali [126]

Answer:

480385.108 in Litres

6 0
2 years ago
What is the molarity of a solution that was prepared by dissolving 82 g of cacl2?
ExtremeBDS [4]

The molarity of a solution is 0.909 M.

m(CaCl₂) = 82 g; mass of calcium chloride

M(CaCl₂) = 111 g/mol; molar mass of calcium chloride

n(CaCl₂) = m(CaCl₂) ÷ M(CaCl₂)

n(CaCl₂) = 82 g ÷ 111 g/mol

n(CaCl₂) = 0.74 mol; amount of calcium chloride

V(CaCl₂) = 812 mL = 0.812 L; volume of calcium chloride

c(CaCl₂) = n(CaCl₂) ÷ V(CaCl₂)

c(CaCl₂) = 0.74 mol ÷ 0.812 L

c(CaCl₂) = 0.909 mol/L = 0.909 M; molarity of calcium chloride

Calcium chloride is a inorganic salt with ionic bonds between calcium and chlorine. It is a colorless crystalline solid at room temperature, highly soluble in water.

More about molarity: brainly.com/question/26873446

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7 0
1 year ago
The standard cell potential for a reaction in an electrolytic cell is always:_____
GuDViN [60]

Answer:

The correct answer is <em>b. Negative</em>

Explanation:

An electrolytic cell is based on a reduction- oxidation reaction which is non spontaneous. That means that the standard cell potencial (Eº) is negative. For this reason, an electrical potential must be applied in order to force the reaction. Conversely, a galvanic cell is based on a spontaneous redox reaction, so the galvanic cell produces electrical energy.

7 0
3 years ago
I need to know 5 and 6
irina [24]
6-cumbustion reaction
7 0
2 years ago
Electroplating is a way to coat a complex metal object with a very thin (and hence inexpensive) layer of a precious metal, such
8_murik_8 [283]

Answer:

0.0164 g

Explanation:

Let's consider the reduction of silver (I) to silver that occurs in the cathode during the electroplating.

Ag⁺(aq) + 1 e⁻ → Ag(s)

We can establish the following relations.

  • 1 A = 1 C/s
  • The charge of 1 mole of electrons is 96,468 C (Faraday's constant)
  • 1 mole of Ag(s) is deposited when 1 mole of electrons circulate.
  • The molar mass of silver is 107.87 g/mol

The mass of silver deposited when a current of 0.770 A circulates during 19.0 seconds is:

19.0s \times \frac{0.770c}{s} \times \frac{1mole^{-} }{96,468C} \times \frac{1molAg}{1mole^{-}} \times \frac{107.87g}{1molAg} = 0.0164 g

5 0
2 years ago
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