The mass of 100 pills would be 78000 mg and 0.078 kilograms.
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A solution with a pH of 6.52 has a hydronium ion concentration of 3.02x10-7 mol/L and a hydroxide ion concentration of 3.31x10-8 mol/L.
The hydronium ion concentration of a solution can be calculated from pH by using 
. For a pH of 6.52, hydronium ion concentration is 3.02x10-7 mol/L.
The concentration of hydroxide ions can be determined by identifying the value of pOH. The sum of pOH and pH is equal to 14, which is based on the negative logarithm of the ion-product constant of water. At a pH of 6.52, pOH is equal to 7.48.
The relationship between pOH and hydroxide ion concentration is the same as the relationship between pH and hydronium ion concentration. With this, the hydroxide ion concentration at pOH of 7.48 is 
or 3.31x10-8 mol/L.
For more information regarding pH and pOH, please refer to the link brainly.com/question/13557815.
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The development of chloroplast is thought to occur through endosymbiosis.
According to the endosymbiosis, some of the organelles found in modern eukaryotic cells, such as mitochondria and chloroplasts, were previously prokaryotic microorganisms. A non-photosynthetic creature acquired one photosynthetic cell, and the chloroplast was subsequently created.
An organelle known as a chloroplast is crucial to the process of photosynthesis in plants. It contains pigments like chlorophyll and other pigments that are in charge of capturing sunlight. Since each chloroplast has two membranes, other organelles such as mitochondria are referred to as double-membrane organelles. It is believed that cyanobacterial endosymbiosis played a role in the genesis of the chloroplast. Prokaryotic organisms like cyanobacteria have the capacity to prepare their food through the process of photosynthesis.
Learn more about endosymbiosis here:
brainly.com/question/15829977
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Answer:
2Na⁺ (aq) and 2OH⁻(aq)
Explanation:
Spectator ions:
Spectator ions are those ions which are same on both side of chemical reaction. These ions are same in the reactant side and product side. Their presence can not effect the chemical equilibrium that's why when we write the net ionic equation these ions are neglect or omitted.
Given ionic equation:
Ba⁺²(aq) + 2OH⁻(aq) + 2Na⁺ (aq) + CO²⁻₃(aq) → BaCO₃(s) + + 2Na⁺ (aq) + 2OH⁻(aq)
In given ionic equation by omitting the spectator ions i.e, 2Na⁺ (aq) and 2OH⁻(aq) net ionic equation can be written as,
Net ionic equation:
Ba⁺²(aq) + CO²⁻₃(aq) → BaCO₃(s)
