Question

What is the value of delta G at 292 for a reaction in which deltaH = 92 kj/mol and delta S= 2.38 kj/mol K

Answer 1

Answer: The value of $\Delta G$ is -602.96 kJ/mol at 292 k for a reaction in which $\Delta H$ = 92 kj/mol and $\Delta S$ = 2.38 kj/mol K.

Explanation:

Given: Temperature = 292 K

$\Delta H$ = 92 kJ/mol

$\Delta S$ = 2.38 kJ/mol

Formula used to calculate the value of $\Delta G$ is as follows.

$\Delta G = \Delta H - T\Delta S$

Substitute the values into above formula as follows.

$\Delta G = \Delta H - T\Delta S\\= 92 kJ/mol - (292 K \times 2.38 kJ/mol K)\\= 92 kJ/mol - 694.96 kJ/mol\\= - 602.96 kJ/mol$

Thus, we can conclude that the value of $\Delta G$ is -602.96 kJ/mol at 292 k for a reaction in which $\Delta H$ = 92 kj/mol and $\Delta S$ = 2.38 kj/mol K.